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crimeas [40]
3 years ago
12

What’s the velocity of an 11-kilogram object with 792 joules of kinetic energy?

Physics
2 answers:
lorasvet [3.4K]3 years ago
4 0

Answer: The velocity of the object is 12 m/s.

Explanation:

Mass of the object = 11 kg

Velocity of the object = v

Kinetic energy possessed by the object  = 792 Joules

K.E=\frac{1}{2}mv^2

792 Joules=\frac{1}{2}\times 11\times v^2

v=\sqrt{\frac{2\times 792 J}{11}}=12 m/s

Hence, the velocity of the object is 12 m/s.

koban [17]3 years ago
3 0
12 m/s is the answer
 
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A trolley has a mass of 1.2 kg and a speed of 4.5 m/s. The trolley crashes into a stationary trolley of mass 0.8 kg. On impact t
attashe74 [19]

(a) The momentum of the first trolley is 5.4 kgm/s

(b) The velocity of the trolleys after impact is 2.7m/s

<u>Explanation:</u>

Given:

Mass, m₁ = 1.2kg

Velocity, v₁ = 4.5m/s

Mass, m₂ = 0.8kg

v₂ = 0

(a) Momentum of the trolley before impact, p

We know:

Momentum = mass X velocity

p = 1.2 X 4.5

p = 5.4 kgm/s

Therefore, the momentum of the first trolley is 5.4 kgm/s

(b) Speed of the trolleys after impact, v = ?

During collision, the momentum is conserved.

So,

m₁v₁ + m₂v₂ = (m₁ + m₂)v

(1.2 X 4.5) + (0.8 X 0) = (1.2 +0.8) X v

5.4 + 0 = 2v

v = 2.7m/s

Therefore, the velocity of the trolleys after impact is 2.7m/s

8 0
3 years ago
What is an apparent change in the frequency of sound or light waves known as?
BartSMP [9]
The apparent change is the Doppler shift
4 0
3 years ago
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Two objects with different masses accelerate at the same rate according to newton’s 2nd law,what must be true about the forces p
nikklg [1K]
The acceleration depends on the mass of an object
8 0
3 years ago
At NASA's Zero Gravity Research Facility in Cleveland, Ohio, experimental payloads fall freely from rest in an evacuated vertica
Diano4ka-milaya [45]

Answer:

(a). Energy is 64,680 J

(b) velocity is 51.43m/s

(c) velocity in mph is 115.0mph

Explanation:

(a).

The potential energy P of the payload of mass m is at a vertical distance h is  

P =mgh.

Therefore, for the payload of mass m = 50kg at a vertical distance of h = 132 m, the potential energy is

P = (50kg)(9.8m/s^2)(132m)

\boxed{P = 64,680J}

(b).

When the payload reaches the bottom of the shaft, all of its potential energy is converted into its kinetic energy; therefore,

mgh= \dfrac{1}{2}mv^2

v= \sqrt{2gh}

v = \sqrt{2*9.8*135}

\boxed{v = 51.43m/s}

(c).

The velocity in mph is

\dfrac{51.43m}{s} * \dfrac{3600s}{hr} * \dfrac{1mile}{1609.34m}

\boxed{v= 115.0mph}

5 0
3 years ago
A boat floats south on the Amazon River at a speed of 6 m/s. The boat and
EleoNora [17]

Explanation:

Take south to be negative.

a. Momentum is mass times velocity.

p = mv

p = (540 kg) (-6 m/s)

p = -3240 kg m/s

p = 3240 kg m/s south

b. Impulse = change in momentum

J = Δp

Since the mass is constant:

J = mΔv

J = (540 kg) (-4 m/s − (-6 m/s))

J = 1080 kg m/s

J = 1080 kg m/s north

7 0
3 years ago
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