Answer:
Magnification, m = 3
Explanation:
It is given that,
Focal length of the lens, f = 15 cm
Object distance, u = -10 cm
Lens formula :
![\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bv%7D-%5Cdfrac%7B1%7D%7Bu%7D%3D%5Cdfrac%7B1%7D%7Bf%7D)
v is image distance
![\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-10)}\\\\v=-30\ cm](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bv%7D%3D%5Cdfrac%7B1%7D%7Bf%7D%2B%5Cdfrac%7B1%7D%7Bu%7D%5C%5C%5C%5C%5Cdfrac%7B1%7D%7Bv%7D%3D%5Cdfrac%7B1%7D%7B15%7D%2B%5Cdfrac%7B1%7D%7B%28-10%29%7D%5C%5C%5C%5Cv%3D-30%5C%20cm)
Magnification,
![m=\dfrac{v}{u}\\\\m=\dfrac{-30}{10}\\\\m=3](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7Bv%7D%7Bu%7D%5C%5C%5C%5Cm%3D%5Cdfrac%7B-30%7D%7B10%7D%5C%5C%5C%5Cm%3D3)
So, the magnification of the lens is 3.
The answer is A I believe. Hope this helps!
Answer:
PV = nRT
Explanation:
the balloon is closed so n is constant
R is constant
If the temperature was constant, a tenfold decrease in pressure would cause a tenfold increase in volume
If the pressure was constant, a threefold decrease in temperature would result in a threefold decrease in volume.
In this situation, the pressure change overwhelms the temperature change so the volume and internal energy both increase