Answer:
Step-by-step explanation:
Note: If you have any queries related the answer please do comment. I would be very happy to resolve all your queries.
Firstly we will make PMF
For X=0, P=(4/5)^3=64/125
For X=1, P=C(3,1)*(1/5)*(4/5)^2=3*16/125=48/125
For X=2, P=C(3,2)*(1/5)^2*(4/5)=3*4/125=12/125
For X=3, P=C(3,3)*(1/5)^3=1/125
So,
E[X^2]=1*48/125+2^2*(12/125)+3^2/125=0.84
E[X]=48/125+12/125*2+1/125*3=0.6
So,
E[X]^2=0.36
Answer:
60 tiles are used
Step-by-step explanation:
1m equals 100 cm.
5m equals 500
3m equals 300
the whole thing is 500 by 300 which when you multiply gives you
150,000. When you multiple 50 by 50 it gives you 2,500. So when you divide 150,000 by 2,500 it gives you a total of 60 tiles. HOPE THIS HELPS
Answer:
depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
Step-by-step explanation:
- First calculate the amount of depreciation/ton
- depreciation per ton = $125,000/208,000 = $0.600 /ton
- Hence depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
All whole numbers are integers, so since 0 is a whole number, 0 is also an integer.
Population = 135 students
Mean score = 72.3
Standard deviation of the scores = 6.5
Part (a): Students from 2SD and 3SD above the mean
2SD below and above the mean includes 95% of the population while 3SD includes 99.7% of the population.
95% of population = 0.95*135 ≈ 129 students
99.7% of population = 0.997*135 ≈ 135 students
Therefore, number of students from 2SD to 3SD above and below the bean = 135 - 129 = 6 students.
In this regard, Students between 2SD and 3SD above the mean = 6/2 = 3 students
Part (b): Students who scored between 65.8 and 72.3
The first step is to calculate Z values
That is,
Z = (mean-X)/SD
Z at 65.8 = (72.3-65.8)/6.5 = 1
Z at 72.3 = (72.3-72.3)/6.5 = 0
Second step is to find the percentages at the Z values from Z table.
That is,
Percentage of population at Z(65.8) = 0.8413 = 84.13%
Percentage of population at (Z(72.3) = 0.5 = 50%
Third step is to calculate number of students at each percentage.
That is,
At 84.13%, number of students = 0.8413*135 ≈ 114
At 50%, number of students = 0.5*135 ≈ 68
Therefore, students who scored between 65.8 and 72.3 = 114-68 = 46 students
