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3 years ago

Any one know what to do

Mathematics

1 answer:

belka [17]3 years ago

6 0

Use pythagorean identity, $9^2+12^2=15^2$ so the answer is 15.

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PLEASE!!! WILL MARK BRAINLIEST IF YOU'RE RIGHTIn this triangle, what is the value of x? enter your answer, rounded to the neares

OLga [1]

$\bold{ANSWER:}$
x = 61.1

$\bold{SOLUTION:}$

6 0

2 years ago

A jar of 150 jelly beans contains 22 red jelly beans, 38 yellow, 20 green, 28 purple, 26 blue, and the rest are orange. Let B =

Oduvanchick [21]

Answer: $\frac{11}{75}$

Step-by-step explanation:

R is the event of getting a red jelly bean. 22 out of the 150 jelly beans are red. That means it is a $\frac{22}{150}$ chance of getting a red jelly bean.

Simplified that is $\frac{11}{75}$

8 0

3 years ago

równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma

Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

$s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\$

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0

3 years ago

What property is 6(2x-3)=6(2x)-6(3)

Setler [38]

Answer:

Distributive property.

Step-by-step explanation:

5 0

3 years ago

1. The probability of telesales representative making a sale on a customer call is 0.15.

Mumz [18]

Answer:

$n = 33$

$n = 19$

Step-by-step explanation:

From the question we are told that

The probability of telesales representative making a sale on a customer call is $p = 0.15$

The mean is $\mu = 5$

Generally the distribution of sales call made by a telesales representative follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the mean is mathematically represented as

$\mu = n* p$

=> $5= n * 0.15$

=> $n = 33$

Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

$P( X \ge 1) = 1 - P( X < 1 ) > 0.95$