:) PERCENTS PLEASE HELP!!

Joshua need an equal number of notepads and sticky notes. How many packages of each item does Joshua need to buy? Notepads has 5

stepan [7]

4 packs of notepads and 5 packs of sticky notes
Explanation: if he needs the same number of both he needs to find the first number that 4 and 5 both go into. 4 x 5 = 20 so this is the least common multiple

8 0

3 years ago

Read 2 more answers

The length of the red line segment is 8, and the length of the blue line segment is 4. How long is the major axis of the ellipse

inessss [21]

Answer: the answer is

C. 12

5 0

3 years ago

Item 3

Soloha48 [4]

Answer: 203

Step-by-step explanation:

to find the area, you have to multiply the length of the sides together. 29x7 = 203

5 0

3 years ago

A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and

natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: $E=k\frac{q}{r^{2} }$ ; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: $p=\frac{q}{A}$ ; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: $S=4\pi r^{2}$ ; which gives us the surface of a sphere.

The inner surface: $Si=4\pi (0.06m)^{2} = 0.04 m^{2}$

The outer surface: $S=4\pi (0.08m)^{2}=0.08m^{2}$

Now we can calculate the charges,

Inner charge: $Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC$

Outer charge: $Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC$

Then, we are able to calculate both fields:

Inner field: $Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}$

Outer field: $Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}$

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0

3 years ago

Can someone please help me this is due in 10 mins

____ [38]

<h2>Answer: 250 Hamburgers sold</h2><h2>Step-by-step explanation:</h2><h2><u><em>x = hamburgers </em></u></h2><h2><u><em>y = cheeseburgers </em></u></h2><h2><u><em>x+y=434 </em></u></h2><h2><u><em>66 fewer cheeseburgers than hamburgers </em></u></h2><h2><u><em> </em></u></h2><h2><u><em> </em></u></h2><h2><u><em>y = x - 66 </em></u></h2><h2><u><em>Substitute y into the first equation </em></u></h2><h2><u><em>x + (x-66) = 434 </em></u></h2><h2><u><em>2x = 434 + 66 </em></u></h2><h2><u><em>2x = 500 </em></u></h2><h2><u><em>x = 250 hamburgers sold</em></u></h2>

7 0

3 years ago