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FinnZ [79.3K]
2 years ago
7

Can you please send help

Mathematics
2 answers:
love history [14]2 years ago
7 0

Answer:

yes ill send the fbi

Step-by-step explanation:

sergeinik [125]2 years ago
4 0
Answer: Yes I can send help to you
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What do you think the answer is?
spin [16.1K]
C. $17.28
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4 0
3 years ago
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Solve for x, rounding to the nearest hundredth.<br> 10^3x = 98
Anna71 [15]

Answer:

see explanation

Step-by-step explanation:

10^3x=98

1000x=98

x=98/1000

x=49/500

x=0.98

if it is rounded to the nearest hundredth then x=0

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3 years ago
Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.
k0ka [10]

Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = \frac{3}{4},

q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28

       = 6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28

       = (\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28

       = (\frac{162}{64})+(\frac{684}{64})-(\frac{720}{64})-\frac{1792}{64}

       = -\frac{1666}{64}

       = -\frac{833}{32} ≠ 0

Therefore, Yuri is not correct. x = \frac{3}{4} can not be a root of the given expression.

6 0
3 years ago
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Answer:

0.8 i think

Step-by-step explanation:

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they can??!!!

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