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3 years ago

The square of the difference of 44 and n into a expression

Mathematics

1 answer:

aleksklad [387]3 years ago

8 0

Answer:

$(44 - n)^2$ would be an expression.

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Jared is correct. 10 stands for y, which needs to be tested by the other y factor on the other side, thus making this equation possible.

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4 years ago

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Describe the rate of change of the function below.

pashok25 [27]

B. Slope is rise over run

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3 years ago

What is the angle relationship between ZBAC and ZDCA?<br> F<br> R<br> G

horsena [70]

The angle BAC and DCA are alternate interior angles , Option D is the right answer.

What are Parallel Lines ?

The lines in a plane which never intersect and are at a same distance always are called Parallel Lines.

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Option D is the right answer.

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2 years ago

I don't understand this question please help

Furkat [3]

Answer:

LM = 22

Step-by-step explanation:

11(44) = (LM)^2

484 = (LM)^2

LM = √484 = 22

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2 years ago

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Find the amount in the bank after 7 years if interest is compounded quarterly?

qwelly [4]

Answer:

a) amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

Step-by-step explanation:

We are given:

Principal Amount P= 5000

Rate r= 4% = 0.04

time t = 7 years

The formula used is: $A=P(1+\frac{r}{n})^{nt}$

where A is future value, P is principal amount, r is rate, n is compounded value and t is time

a) Find the amount in the bank after 7 years if interest is compounded quarterly?

If interest is compounded quarterly then n = 4

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{4})^{4*7} \\A=5000(1+0.01)^{28}\\A=5000(1.01)^{28}\\A=5000(1.321)\\A=6,605$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) Find the amount in the bank after 7 years if interest is compounded monthly?

If interest is compounded quarterly then n = 12

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{12})^{12*7} \\A=5000(1+0.003)^{84}\\A=5000(1.003)^{84}\\A=5000(1.322)\\A=6,612.57$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

6 0

3 years ago