This question is incomplete, the complete question;
The American Psychological Associated conducted a survey in 2003 of psychologists to estimate the average incomes for psychologists based on their academic degree and years of experience. 36 psychologists responded who had a just received their masters degree in 2003. The average was $48,800 with a standard deviation of $16,800.
The 95% Confidence Interval is ($, $ )
Answer:
at 95%, confidence interval is ( $43312, $54288 )
Step-by-step explanation:
Given the data in the question;
sample size n = 36
mean x' = 48,800
standard deviation σ = 16,800
at 95% confidence level;
∝ = 1 - 95% = 1 - 0.95 = 0.05
∝/2 = 0.05 / 2 = 0.025
z critical value, = 1.96
now, confidence interval for population mean is given by the formula
x' ± ( σ/√n )
so we substitute
⇒ 48800 ± 1.96( 16800/√36 )
⇒ 48800 ± 1.96( 2800 )
⇒ 48800 ± 5488
⇒ 48800 - 5488, 48800 + 5488
⇒ ( 43312, 54288 )
Therefore, at 95%, confidence interval is ( $43312, $54288 )
Answer:
Step-by-step explanation:
we know that
In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference
we have
Let
The common difference is
We can write an Arithmetic Sequence as a rule
where
a_n is the nth term
d is the common difference
a_1 is the first term
n is the number of terms
Find the 63rd term of the arithmetic sequence
we have
substitute