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fomenos
2 years ago
11

Calculate the length of the side BC. Using pythagoras ​

Mathematics
2 answers:
olchik [2.2K]2 years ago
5 0
It’s 10m. If you know about Pythagorean triples, one of the triplets is 6,8,10. The other way is the Pythagorean Theron which is a^2 +b^2=c^2. So if we plug it in it would be 6m^2+8m ^2=am^2. So 6m^2+8m ^2 would be equal to 100m^2. Then you would have to find the square root of it to get 10m.
o-na [289]2 years ago
3 0

Answer:

10m

Step-by-step explanation:

<em><u>A^2+B^2=C^2</u></em>

<em><u>6^2+8^2=C^2</u></em>

36+64=C^2

100=C^2

10=C

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How do you find the original price when given the sale price and the percent of the discount
liberstina [14]
<span><span>The rate is usually given as a percent.
</span><span>To find the discount, multiply the rate by the original price.
</span>To find the sale price, subtract the discount from original price.</span>
5 0
3 years ago
Bob has a standard deck of playing cards. If he randomly draws a J, K, 2, and 2, what is the probability that the next card he d
nlexa [21]

Answer:

The correct answer has already been given (twice). I'd like to present two solutions that expand on (and explain more completely) the reasoning of the ones already given.


One is using the hypergeometric distribution, which is meant exactly for the type of problem you describe (sampling without replacement):


P(X=k)=(Kk)(N−Kn−k)(Nn)


where N is the total number of cards in the deck, K is the total number of ace cards in the deck, k is the number of ace cards you intend to select, and n is the number of cards overall that you intend to select.


P(X=2)=(42)(480)(522)


P(X=2)=61326=1221


In essence, this would give you the number of possible combinations of drawing two of the four ace cards in the deck (6, already enumerated by Ravish) over the number of possible combinations of drawing any two cards out of the 52 in the deck (1326). This is the way Ravish chose to solve the problem.


Another way is using simple probabilities and combinations:


P(X=2)=(4C1∗152)∗(3C1∗151)


P(X=2)=452∗351=1221


The chance of picking an ace for the first time (same as the chance of picking any card for the first time) is 1/52, multiplied by the number of ways you can pick one of the four aces in the deck, 4C1. This probability is multiplied by the probability of picking a card for the second time (1/51) times the number of ways to get one of the three remaining aces (3C1). This is the way Larry chose to solve the this.

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
tim earns $150/week plus $15.00 for each desk he assembles. Write an inequality to represent how many desks he needs assemble to
Gennadij [26K]

x = number of desks needed to make

equation:  150 +15.50x >= 400


solution:

150 +15.50x >=400

15.50x = 250

x = 250/15.50 = 16.129

he needs to assemble 17 desks

15.50*17 = 263.50 +150 = $413.50


3 0
3 years ago
8x-3y=6-4x in linear equation
castortr0y [4]
It would be y=4x-2 because:
8x-3y=6-4x
-8x         -8x
-3y=6-12x
/-3  /-3 /-3
y=-2+4x
y=4x-2
4 0
3 years ago
5.
RSB [31]

D. is the answer.

your welcome hunty

8 0
3 years ago
Read 2 more answers
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