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just olya [345]
3 years ago
9

Point C is the midpoint of a segment AB . What are the coordinates of point B, if: A(–1, 3), C( 1, –1)

Mathematics
2 answers:
a_sh-v [17]3 years ago
5 0

Answer:

(3,-5)

Step-by-step explanation:

To find the x coordinate of the  midpoint, add the  x coordinates together and divide by 2

The x coordinate is

(x1+x2)/2

We know one point and the midpoint

( -1+x)/2 = 1

Multiply by 2

-1 +x = 2

Add 1

x =2+1

x=3

To find the y coordinate of the midpoint, add the  y coordinates together and divide by 2

The y coordinate is

(y1+y2)/2

We know one point and the midpoint

(3+y)/2 = -1

Multiply by 2

3+y = -2

Subtract 3

y = -2-3

y =-5

The other endpoint is (3,-5)

Andrew [12]3 years ago
5 0

Answer:

B(3, -5)

Step-by-step explantion

We know that these formulas can be used to find the mid point between 2 points on a graph

\frac{a_{1} +b_{1}}{2}= c_{1}\\   \frac{a_{2} +b_{2}}{2} =c_{2}

Now we plot these points in

A(-1, 3), C(1, -1)

\frac{-1+b_{1}}{2} =1  \\\frac{3+b_{2}}{2} =1

And we can find that

b_{1}= 3\\b_{2}=-5

Therefore we get the answer of (3, -5)

Hope that helped you with your problem!! :)

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I can’t figure out how to use the zeros in the polynomial. Please explain
Temka [501]

Answer:

a) P (x) = (x + 3) (x-1) (x-4)

b) P (x) = (2x + 5) (5x - 4) (x-6)

c) P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

P (x) = (x + 3) (x-1) (x-4)

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0

---------------------------------------

x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0

--------------------------------------

x = 6\\\\(x-6) = 0

--------------------------------------

P (x) = (2x + 5) (5x - 4) (x-6)

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

x = -3\\\\(x-3) = 0

--------------------------------------

x = 1\\\\(x-1) = 0

--------------------------------------

x = 4\\\\(x-4) = 0

----------------------------------------

x = -1\\\\(x + 1) = 0

-----------------------------------------

P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

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Step-by-step explanation:

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