SOMEONE HELP MEEEE PLEASE

Patel squeezed oranges so that his family could have fresh-squeezed juice for breakfast. He squeezed StartFraction 4 over 17 End

dlinn [17]

Answer:

A. 1/2 cups

Step-by-step explanation:

13/15 is close to 1

1/5 is a small amount

9/20 is just over 1/2

5/11 is just under 1/2

7/15 is just under 1/2

Estimate: 1 + 1/2 + 1/2 + 1/2 + a little = 2 1/2

He needs 3 cups, so he needs another 1/2 cup.

Answer: A. 1/2 cups

5 0

2 years ago

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It is Monday, 0250 hours in Vancouver, Canada, and Monday, 2050 hours in Melbourne. By how many hours is Vancouver time behind M

NikAS [45]

The answer is 1800

How to get it

2050 - 250=
do the subtraction
and Vancouver is 1800 hours behind Melbourne

7 0

3 years ago

The graph shows how the mass of copper

Alex777 [14]

Answer: 8 1/4g/cm³

Step-by-step explanation:

Given the graph :

The rate of change in the mass of copper with respect to volume :

To obtain this, we find the slope or gradient of the graph:

Gradient = Δy / Δx = (y2 - y1) / (x2 - x1)

Drawing a right angled triangle on the anybpart of the line of best fit:

y2 = 40 ; x2 = 4.75 ; y1 = 16 ; x1 = 2

(y2 - y1) / (x2 - x1)

= (40 -16) / (4.75 - 2)

= 24 / 2.75

= 2400/275

= 8.727 g/cm^3

Due to unit and graph scale,, the slope is closest to 8 1/4g/cm³

6 0

2 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

2 years ago

The function g is defined by the following rule. g(x)=5x-4 <br> complete the function table

Elan Coil [88]

(-4,-24) (-1,-9) (1,1) (2,6) (4,16)

8 0

2 years ago

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