SOMEONE HELP MEEEE PLEASE

Please help work is due tomorrow. Thanks

melamori03 [73]

The answer is D it has a right angle

6 0

4 years ago

Mark made a scale drawing of a soccer field, using a scale of .5 cm=1m. The actual length of the field is 110 m. What is the len

nataly862011 [7]

Answer:

The length of the field on the drawing is 55 cm.

Step-by-step explanation:

Given:

Mark made a scale drawing of a soccer field.

Using a scale of .5 cm=1 m.

The actual length of the field is 110 m.

Now, to find the length of the field on drawing.

Let the length of the field on drawing be $x.$

As given 0.5 cm is equivalent to 1 m.

Thus, $x$ is equivalent to 110 m.

Now, to get the length of the field on drawing by using cross multiplication method:

$\frac{0.5}{1} =\frac{x}{110}$

<em>By cross multiplying we get:</em>

⇒ $55=x$

⇒ $x=55$

Therefore, the length of the field on the drawing is 55 cm.

8 0

3 years ago

Simplify -3/5 + 13/55

trasher [3.6K]

Answer:

-4/11 or -0.36363

Step-by-step explanation:

;)

5 0

3 years ago

Read 2 more answers

(sinA-cosA+1)/(sinA+cosA-1)=2(1+cosecA)

borishaifa [10]

Answer:

The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

Step-by-step explanation:

Given Trigonometrical function as :

$\frac{sin A - cos A + 1}{sin A + cos A - 1}$ = 2 (1 + cosec A)

Or, $\frac{sin A + ( 1 - cos A)}{sin A - (1 - cos A)}$ = 2 (1 + cosec A)

,<u> Now, rationalizing </u>

$\frac{(sin A + ( 1 - cos A)) \times (sin A + (1 - cosA))}{(sin A - (1 - cos A))\times (sin A + (1 - cos A))}$ = 2 (1 + cosec A)

Or, $\frac{(sin A + (1 - cos A))^{2}}{sin^{2} - (1-cos A)^{2}}$ = 2 ( 1 + $\dfrac{1}{\textrm sinA}$

Or, $\frac{sin^{2}A + (1 - cosA)^{2} + 2 \times sin A \times (1 - cos A)}{sin^{2}A - (1 + cos^{2}A - 2 cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - 1 - cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - (sin^{2}A + cos^{2}A) - cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{2- 2 cos A + 2 sin A - 2 sin A cos A}{- 2cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{1- cos A + sin A - sin A cos A}{- cos^{2}A + cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1- cos A) + sin A (1-cos A)}{cos A(1 - cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1- cos A) (1 + sinA)}{cos A(1 - cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1 + sinA)}{(cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, sin A + sin² A = 2 cos A (1 + sin A)

Or, sin A + sin² A = 2 cos A + 2 cos A × sin A

Or, sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

So,The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0 Answer

6 0

3 years ago

FIND THE VOLUME OF THE PRISM

ki77a [65]

Answer:

volume of prism is 157.464

6 0

3 years ago