Answer:
A. 1/2 cups
Step-by-step explanation:
13/15 is close to 1
1/5 is a small amount
9/20 is just over 1/2
5/11 is just under 1/2
7/15 is just under 1/2
Estimate: 1 + 1/2 + 1/2 + 1/2 + a little = 2 1/2
He needs 3 cups, so he needs another 1/2 cup.
Answer: A. 1/2 cups
Answer: 8 1/4g/cm³
Step-by-step explanation:
Given the graph :
The rate of change in the mass of copper with respect to volume :
To obtain this, we find the slope or gradient of the graph:
Gradient = Δy / Δx = (y2 - y1) / (x2 - x1)
Drawing a right angled triangle on the anybpart of the line of best fit:
y2 = 40 ; x2 = 4.75 ; y1 = 16 ; x1 = 2
(y2 - y1) / (x2 - x1)
= (40 -16) / (4.75 - 2)
= 24 / 2.75
= 2400/275
= 8.727 g/cm^3
Due to unit and graph scale,, the slope is closest to 8 1/4g/cm³
Answer:
32.66 units
Step-by-step explanation:
We are given that

Point A=(-2,-4) and point B=(1,20)
Differentiate w.r. t x

We know that length of curve

We have a=-2 and b=1
Using the formula
Length of curve=
Using substitution method
Substitute t=12x+14
Differentiate w.r t. x


Length of curve=
We know that

By using the formula
Length of curve=![s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B1%7D%7B12%7D%5B%5Cfrac%7Bt%7D%7B2%7D%5Csqrt%7B1%2Bt%5E2%7D%2B%5Cfrac%7B1%7D%7B2%7Dln%28t%2B%5Csqrt%7B1%2Bt%5E2%7D%29%5D%5E%7B1%7D_%7B-2%7D)
Length of curve=![s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B1%7D%7B12%7D%5B%5Cfrac%7B12x%2B14%7D%7B2%7D%5Csqrt%7B1%2B%2812x%2B14%29%5E2%7D%2B%5Cfrac%7B1%7D%7B2%7Dln%2812x%2B14%2B%5Csqrt%7B1%2B%2812x%2B14%29%5E2%7D%29%5D%5E%7B1%7D_%7B-2%7D)
Length of curve=
Length of curve=
Length of curve=
(-4,-24) (-1,-9) (1,1) (2,6) (4,16)