Answer:
x= 5 , x = -1
Step-by-step explanation:
4|x-2|=12
|x-2| = 3
x-2 = 3
x = 5
x-2 = -3
x= -1
True! If you have any 3 segments, it could form a triangle, just not a right triangle.
Keywords
quadratic equation, discriminant, complex roots, real roots
we know that
The formula to calculate the <u>roots</u> of the <u>quadratic equation</u> of the form
is equal to

where
The <u>discriminant</u> of the <u>quadratic equation</u> is equal to

if
----> the <u>quadratic equation</u> has two <u>real roots</u>
if
----> the <u>quadratic equation</u> has one <u>real root</u>
if
----> the <u>quadratic equation</u> has two <u>complex roots</u>
in this problem we have that
the <u>discriminant</u> is equal to 
so
the <u>quadratic equation</u> has two <u>complex roots</u>
therefore
the answer is the option A
There are two complex roots
The problem is -2a - 5 > 3
we have - 2a>3+5
or - 2a>8 and now we divide by - 2
and a< 8/(-2) or a< -4
That means you have to choose D- the last line