Answer:
See below. No image this time.
Step-by-step explanation:
1.
- P(2, 8) → P'(-5, 1), which it went 7 units to the left, and 7 units down. Here is the equation: (x - 7, y - 7).
2.
- R(-4, -9) → R'(-4, -2), which went 7 units up. Here is the equation: (x, y + 7).
3.
- M(10, -3) → M'(3, 4), which went 7 units left, 7 units up. Here's the equation: (x - 7, y + 7).
4.
- K(7, 11) → K'(0, 11), which went 7 units left. Here is the equation: (x - 7, y).
Answer:
22.86% probability that the persons IQ is between 110 and 130
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

If one person is randomly selected what is the probability that the persons IQ is between 110 and 130
This is the pvalue of Z when X = 130 subtracted by the pvalue of Z when X = 110.
X = 130



has a pvalue of 0.9772
X = 110



has a pvalue of 0.7486
0.9772 - 0.7486 = 0.2286
22.86% probability that the persons IQ is between 110 and 130
X^2+4+10=0
x=(-4(+/-)root16-40)/2, so we now know that the zeros are imaginary, because you can't square root a negative number and 16-40 is -24
so the two roots are…
-2+iroot6 and -2-iroot6
I think it’s b! i hope that helps!
.8 it represents .80 cents. rather than .08 which would represent 8 pennies