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3 years ago

HELP ASAP PLS

Mathematics

1 answer:

Schach [20]3 years ago

8 0

Maybe 4.16 not sure but best

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5x -30 = 3x + 60<br> How many solutions are there

Lynna [10]

Answer:

one solution

Step-by-step explanation:

5x - 30 = 3x + 60

2x - 30 = 60

2x = 90

x = 45

4 0

3 years ago

expand and simplify completely (log). PLEASEE HELP ASAP!!! I WILL GIVE BRAINLIEST!! thank you so much!!!!

r-ruslan [8.4K]

Answer:

c. $2 log3(y)+1+log3(x)$

Step-by-step explanation:

When expanding and simplifying, we can see that the answer is $1+log3(x) + 2log3(y)$ , which matches Answer Choice C.

7 0

3 years ago

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you buy popcorn and a soda at the movies. A large popcorn is $7.00 and a drink is $3.50. Tax is 6%. How much will you pay?

Jobisdone [24]

Answer:

$11.13

Step-by-step explanation:

$7.00 + $3.50 = $10.50

6% of $10.50 is $0.63

$10.50 + 0.63 = $11.13

6 0

4 years ago

The cost of a long distance call is $1.25 for the

Vinil7 [7]

C

For first 3 minutes keep 1.25
Then for rest do 0.15(x-3)
Now add to get total cost

Mark brainliest please

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3 years ago

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(5x^3-8x^2+9x+12)/(x-3)<br><br> please answer with sentences on how to do it step by step. thanks!

Anastaziya [24]

Answer:

$5x^2+7x+30+\frac{102}{x-3}$

Step-by-step explanation:

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}$

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\$

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}30x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{30x}{x}=30\\\mathrm{Quotient}=30\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}30:\:30x-90\\\mathrm{Subtract\:}30x-90\mathrm{\:from\:}30x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=102\\\mathrm{Therefore}\\=5x^2+7x+30+\frac{102}{x-3}$

6 0

3 years ago

Read 2 more answers