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2 years ago

Which relation is a function?

Mathematics

1 answer:

kirill115 [55]2 years ago

7 0

Answer:

Step-by-step explanation:

The graph certainly is, if you ignore the fact that you don't know what the equation for the graph is.

Each x has only 1 y associated with it. That's the definition of a function. This one presumably follows that definition, but I caughten you, without the equation, you can't be sure.

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C is the midpoint of AD. B is the midpoint of AC. BC = 12. What is the length of AD

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3 years ago

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Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

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3 years ago

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Step-by-step explanation:

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3 years ago

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3 years ago

6a2 + 8a - 25 = -3<br> Using the Quadratic Formula

drek231 [11]

Answer:

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6a^{2}+8a-25=-3

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Step-by-step explanation:

0/3

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