Answer:
0.00002 = 0.002% probability of actually having the disease
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Positive test
Event B: Having the disease
Probability of having a positive test:
0.05 of 1 - 0.000001(false positive)
0.99 of 0.000001 positive. So

Probability of a positive test and having the disease:
0.99 of 0.000001. So

What is the probability of actually having the disease

0.00002 = 0.002% probability of actually having the disease
5/34 is the answer for this problem
Answer:
she brought 21 shirts and 2 pants
Step-by-step explanation:
shirts
21× 14.50 = 304.5
357- 304.5 = 52.5
pants
52.5 ÷ 25 = 2.1
Answer:
width=x
length=5x
area= 300ft2
area=lxb
300=5x(x)
300=5x^2
x^2=60
x=7.74
7.74(5)=38.7
dimensions are 38.7ft by 7.74 ft
<u><em>Please mark as brainliest</em></u>
(x+4)^2 / 9 - (y+3)^2 / 16 = 1
a^2 = 16 and b^2 = 9
a = +4 and -4
b = +3 and -3
Center is (-4, -3)
Vertices is (-4 + a, -3) and (-4 - a, -3)
Vertices is (-1, -3) and (-7, -3)