Substitution is best to use one one or both equations is already solved for one of the variables. Elimitation can be use if all variables have a coefficient other than 1.
Answer: -$6,500
Step-by-step explanation:
Here we could , use the arithmetic progression where
T(2020 - 2010) = a + ( n - 1 )d
T10 = a + ( 10 - 1 )d --------------- 1
a = $25,000, n = 10 and d = 14% of $25,000 = $3,500 the common difference.
Note since it decreases the common difference d = -$3,500.
Now substitute for the values in the equation above.
T10 = 25,000 + 9 x -3,500
= $25,000 - $31,500
= -$6,500 (deficit )
Answer:
66.4°
Step-by-step explanation:
→ Find the side which is not given
Hypotenuse = 15 cm
Opposite = ?
Adjacent = 6 cm
→ Utilise the formula triangle with out opposite in it
Cos⁻¹ = Adjacent ÷ Hypotenuse
→ Substitute in the terms
Cos⁻¹ = 6 ÷ 15 ⇔ 66.4°
Answer: 
Step-by-step explanation:
