3 years ago

Suppose c varies jointly with a and b. When c = 25, a = 2, and b = 2.5. What is the value of c when b = 4/3 and a = 6?

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

8 0

You have to find the value of c when b=4/3and a=6

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BRAINLIESTT ASAP! PLEASE HELP ME :)

Lubov Fominskaja [6]

Answer: $\sqrt{37}$

=====================================

Work Shown:

6x-y = -3 is the same as 6x-y+3 = 0

6x-y+3 = 0 is the form Ax+By+C = 0 with A = 6, B = -1, C = 3.

The distance d that line is from the point (p,q) = (6, 2) is found by the following

$d = \frac{A*p+B*q+C}{\sqrt{A^2+B^2}}\\\\d = \frac{6*6-1*2+3}{\sqrt{6^2+(-1)^2}}\\\\d = \frac{36-2+3}{\sqrt{36+1}}\\\\d = \frac{37}{\sqrt{37}}\\\\d = \frac{37\sqrt{37}}{37}\\\\d = \sqrt{37}\\\\d \approx 6.08276\\\\$

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3 years ago

What is the equation of the graphed line in point-slope form?

Alenkinab [10]

(3,1)(-3,-3)
slope = (-3 - 1) / (-3 - 3) = -4/-6 = 2/3

y - y1 = m(x - x1)
slope(m) = 2/3
(3,1)....x1 = 3 and y1 = 1
now sub
y - 1 = 2/3(x - 3) <===

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disa [49]

Hey there!!

Given:

... 7x-8=4+3x

... 4x-8=4

... 4x=12

... x=12/4

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Hence, the required answer is 3.

Hope it helps!

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