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julia-pushkina [17]
3 years ago
13

Suppose c varies jointly with a and b. When c = 25, a = 2, and b = 2.5. What is the value of c when b = 4/3 and a = 6?

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
8 0
You have to find the value of c when b=4/3and a=6
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Of 30 students 1/3 play sports. Of those who play sports 2/3 play soccer. How may students play soccer?
Orlov [11]

Answer:

4

Step-by-step explanation:

1/3 of 30 students play sport

30×1/3

= 10

2/5 of this number plays soccer

10×2/5

= 20/5

= 4

5 0
2 years ago
Factor 25x 2 + 10x + 1.
scoundrel [369]
25x^2+10x+1
(25x^2+5x)(+5x+1)
5x(5x+1) +1(5x+1)
(5x+1) (5x+1)
X=1/5
3 0
3 years ago
Read 2 more answers
9 cm + 2.8 cm = 11.8
den301095 [7]
It depends on the precision you want.

Considering the data you've given, if you want the result in cm, the numbers should be rounded to 9 and 3, thus giving a total of 12, with two significant numbers.

But taking into account the precision you've reported, looks like the decimals do matter, and in that case, the numbers should be rounded to 9.0 and 2.8, giving a total of 11.8, thus, three significative figures.
4 0
3 years ago
Read 2 more answers
1.28 x 10^5) + (113 x 10^3)=​
Evgesh-ka [11]

Answer:

241,000

Step-by-step explanation:

When multiplying a number with a base of 10 raised to the nth power. Move the decimal point of that number n digits to the right.

(1.28 \times  {10}^{5} ) + (113 \times  {10}^{3} )

128000  \:  +  \: 113000

241000

4 0
3 years ago
I’m pretty sure it’s 30 or 120?
Diano4ka-milaya [45]
I believe it’s 120? Not for sure tho so don’t quote me
6 0
3 years ago
Read 2 more answers
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