Someone help me please

Mathematics

1 answer:

gayaneshka [121]3 years ago

6 0

The answer is d hope it helps

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Write an equation of the line passing through the point A(2, 0) that is parallel to the line y = 3x−5

satela [25.4K]

Answer:

y = 3x-6

Step-by-step explanation:

y = 3x−5

This is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

m =3

Parallel lines have the same slope

We have the slope m=3 and a point (2,0)

y = mx+b

y = 3x+b

Substituting the point into the equation to solve for b

0 = 3(2)+b

0 = 6+b

b = -6

y = 3x-6

4 0

3 years ago

Read 2 more answers

What is the equation of the graph

AveGali [126]

Answer:

$y = 2x^2 + 1$

Step-by-step explanation:

The graph you see there is called a parabola. The general equation for the graph is as below

$y = a*x^2 + b$

To find the equation we need to find the constants a and b. The constant b is just how much we're lifting the parabola by. Notice it's lifted by 1 on the y axis.

To find a it's a little more tricky. Let's use the graph to find a value for a by plugging in values we know. We know that b is 1 from the previous step, and we know that when x=1, y=3. Let's use that!

$3 = a * (1)^2 + 1\\2 = a$