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ankoles [38]
3 years ago
7

Find the length of AD in the diagram shown. A) 7 B) 7.5 C) 9 D 16.5

Mathematics
2 answers:
frosja888 [35]3 years ago
8 0
C.9 is the right answer
Tanya [424]3 years ago
5 0

Answer: 16.5

Step-by-step explanation:

The correct answer is given :) , for proof please select the picture in order to understand.

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Measuring and arcs.
n200080 [17]

Answer:

Hope this helps

Step-by-step explanation:

3. Minor arc, 44°

4. Major arc, 140°

5. Minor arc, 44°

6. Major arc, 316°

7. Semi circle, 180°

8. Major arc, 140°

9. 38°

10. 52°

11. 142°

12. 128°

13. 232°

14. 308°

7 0
3 years ago
How are the mean and median affected when the value 5 is included in the data set belo
Kobotan [32]

Answer:

The mean increases and the median changes to 4.

Step-by-step explanation:

To find the mean. You need to add all of the numbers together then divide by how many numbers there are. The median is found by the middle number.

3 0
2 years ago
Read 2 more answers
Complete the statement.<br> L=234 mL
Andru [333]

Answer:

0.234

Step-by-step explanation:

3 0
3 years ago
The average car decreases in value by about 15% per year. If a car's original value is $28,000, which function best represents i
andrey2020 [161]

Answer:

D

Step-by-step explanation:

D

6 0
3 years ago
For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?
DaniilM [7]
<h2>Answer:</h2>

The values of x for which the given vectors are basis for R³ is:

                        x\neq 1

<h2>Step-by-step explanation:</h2>

We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

(-1,0,-1), (2,1,2), (1,1, x)

The matrix formed by these vectors is:

\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]

Now, the determinant of this matrix is:

\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-1(x-2)-2(1)+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+2-2+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+1

Hence,

-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1

4 0
3 years ago
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