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Anvisha [2.4K]
3 years ago
8

Randy filled out a deposit slip today. He deposited two checks for $123.17 and $34.68 and took out $50 in cash

Mathematics
2 answers:
erica [24]3 years ago
7 0
What he has left in the bank is here :

(123.17 + 34.68) - 50 = 107.8

He still has $107.8 left in the bank and he has $50 in his pocket.

I hoped I helped!
Delicious77 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

Since Randy filled out a deposit slip and deposited two checks

his balance would increase by the cheque amounts.

I cheque amount = 123.17

II cheque amount  =  34.68

Total deposit          = 157.85

So his balance would increase by 157.85 dollars because of deposit of two cheques

Since he withdraws 50 dollars in cash, his balance would reduce by 50 dollars

So net increase in balance in bank account = 157.85 -50 =107.85 dollars

His cash in hand increases by 50 dollars.

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Answer

60073

explanation

3^10 + 4^5 = 60073
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20.000 + 4.000 + 0.300 + 0.050 + 0.007
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Write the polynomial in factored form. <br><br> p(x)=(x+5)(x-___)(x+___)
Rom4ik [11]

Answer:


Step-by-step explanation:

Given : p(x)=x^{3} +6x^{2} -7x-60

Solution :

Part A:

First find the potential roots of p(x) using rational root theorem;

So, \text{Possible roots} =\pm\frac{\text{factors of constant term}}{\text{factors of leading coefficient}}

Since constant term = -60

Leading coefficient = 1

\text{Possible roots} =\pm\frac{\text{factors of 60}}{\text{factors of 1}}

\text{Possible roots} =\pm\frac{1,2,3,4,5,6,10,12,15,20,60}{1}

Thus the possible roots are  \pm1, \pm2, \pm 3, \pm4, \pm5,\pm6, \pm10, \pm12, \pm15, \pm20, \pm60

Thus from the given options the correct answers are -10,-5,3,15

Now For Part B we will use synthetic division

Out of the possible roots we will use the root which gives remainder 0 in synthetic division :

Since we can see in the figure With -5 we are getting 0 remainder.

Refer the attached figure

We have completed the table and have obtained the following resulting coefficients: 1 , 1,−12,0.  All the coefficients except the last one are the coefficients of the quotient, the last coefficient is the remainder.

Thus the quotient is x^{2} +x-12

And remainder is 0 .

So to get the other two factors of the given polynomial we will solve the quotient by middle term splitting

x^{2} +x-12=0

x^{2} +4x-3x-12=0

x(x+4)-3(x+4)=0

(x-3)(x+4)=0

Thus x-3 and x+4 are the other two factors

So , p(x)=(x+5)(x-3)(x+4)





3 0
3 years ago
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Find the 8th term of the geometric sequence whose common ratio is 2/3 and whose first term is 7​
motikmotik

Answer:

The 8th term of the sequence is 896/2187.

Step-by-step explanation:

We want to find the 8th term of a geometric sequence whose common ratio is 2/3 and whose first term is 7.

We can write a direct formula. Recall that the direct formula of a geometric sequence is given by:

\displaystyle x_{n} = a\left(r\right)^{n-1}

Where <em>a</em> is the initial term and <em>r</em> is the common ratio.

Substitute:

\displaystyle x_{n} = 7\left(\frac{2}{3}\right)^{n-1}

To find the 8th term, let <em>n</em> = 8. Substitute and evaluate:

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