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Svetradugi [14.3K]
3 years ago
9

Can you please help me

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0

Answer: Was there supposed to be a picture here?

Step-by-step explanation: If there was supposed to it isn't here

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What is the value of x for this question?
cestrela7 [59]

Answer:

Step-by-step explanation:

3x + 3

6 + 2x

3x + 2x = 5x

3 + 6 = 9

5x + 9

4 0
3 years ago
Jake, Kim and Lee share some money in the ratio 1 : 3 : 6.
Scrat [10]

Answer:

£27.00

Step-by-step explanation:

3 × £9 = £27 amount Lee gets

3 0
3 years ago
Try This one out and I’ll give you brainliest no links or I will report you Thank you
sladkih [1.3K]

Answer:

32. steps below.

Step-by-step explanation:

So calculate 4(2x2^3-8)

=

4(2^4-8)

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3 0
2 years ago
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You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu
aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to 180^{o}.

Let the exterior angle be represented by x^{o}, and the three interior angles of the triangle be represented by a^{o}, b^{o} and c^{o}.

Assume that the vertex angle c^{o} is the linear pair to the exterior angle x^{o}.

i.e            x^{o} + c^{o} = 180^{o}  (sum of angles on a straight line)

Thus,

i. a^{o} +  b^{o} = x^{o}  (sum of two opposite interior angles is equal to an exterior angle)

⇒ a^{o}  = x^{o} - b^{o}

Also,

b^{o}  = x^{o} - a^{o}

But,

a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

⇒ c^{o} = 180^{o} - (a^{o} +  b^{o})

and

a^{o} + b^{o} = 180^{o} - c^{o}

ii. a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

a^{o} = 180^{o} - (b^{o} + c^{o})

Also,

a^{o} +  b^{o} = x^{o}

⇒ b^{o} = x^{o} - a^{o}

c^{o} = 180^{o} - x^{o}

8 0
3 years ago
Refer to the table. Which lap has the slowest time
Alecsey [184]

Lap 2 because the bigger the number in time the longer.


7 0
3 years ago
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