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SIZIF [17.4K]
3 years ago
15

According to the image below, which season is about to begin in the southern hemisphere?

Mathematics
2 answers:
OLEGan [10]3 years ago
8 0
I think the answer is summer
Novosadov [1.4K]3 years ago
8 0

Answer:

summer

Step-by-step explanation:

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A) how many 15-year old students took part in the survey?
trapecia [35]

Answer: 60 or something near that sorry if wrong

Step-by-step explanation:

8 0
3 years ago
Pls answer you’ll get 100 points
Dahasolnce [82]

Take 2points

  • (0,0)
  • (3,2)

Equation in two point form

\\ \sf\longmapsto y-y_1=\left(\dfrac{y_2-y_1}{x_2-x_1}\right)x-x_1

\\ \sf\longmapsto y-0=\dfrac{2-0}{3-0}(x-0)

\\ \sf\longmapsto y=\dfrac{2}{3}x

.

Option D is correct

8 0
2 years ago
Read 2 more answers
Hewo Please Help THX!!! :)
Serga [27]

Answer:

$30

Step-by-step explanation:

x =4(3.45)+1.5(3.98)+2(4.35)+1.53

=13.8+5.97+8.7+1.53

=30

6 0
2 years ago
A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th
ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

H_0: \mu=500\\\\H_a:\mu< 500

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1

The degrees of freedom for this sample size are:

df=n-1=5-1=4

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

4 0
3 years ago
Can u help me with my work don’t send a link !!
Vlad [161]

Answer:

$503.35

Step-by-step explanation:

you just have to plug in the value of each variable into the equation

i hope this helps :)

7 0
2 years ago
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