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Gekata [30.6K]
3 years ago
5

Would you rather use color tiles or your ruler to measure the length of an object

Mathematics
2 answers:
Ronch [10]3 years ago
7 0
Id rather use a ruler 
Step2247 [10]3 years ago
4 0
A ruler to measure the length of an object.
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Circle A is tangent to circle B. True False
astraxan [27]

Answer:

is there a picture

Step-by-step explanation:


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Sine, cosine, and tangent are used when looking for a missing side length in the right triangle. True or False
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Is 3/2 greater than 1? Or Less than
Simora [160]

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3/2 is greater than 1

Step-by-step explanation:

A little trick to immediately know if a number is more or less than when it involves fractions versus whole numbers is that improper fractions will always be greater than 1.

If you want to confirm this, dividing 3/2 equals 1.5, ergo 1.5 > 1.

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Simplify (3x − 5) − (5x + 1). (2 points)
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Approximate the change in the volume of a sphere when its radius changes from r​ = 40 ft to r equals 40.05 ft (Upper V (r )equal
alexgriva [62]

Answer:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere (V), measured in cubic feet, is represented by the following formula:

V = \frac{4\pi}{3}\cdot r^{3}

Where r is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

\Delta V = \frac{\partial V}{\partial r}\Delta r

The derivative of the volume as a function of radius is:

\frac{\partial V}{\partial r} = 4\pi \cdot r^{2}

Then, the change in volume is expanded:

\Delta V = 4\pi \cdot r^{2}\cdot \Delta r

If r = 40\,ft and \Delta r = 40\,ft-40.05\,ft = 0.05\,ft, the change in the volume of the sphere is approximately:

\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)

\Delta V \approx 1005.310\,ft^{3}

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

7 0
3 years ago
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