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NISA [10]
3 years ago
15

A1 kg object is located at a distance of 6.4 x10^6 m from the center of a larger object whose mass is 6.0 x 10^24 kg. Find the g

ravitational attraction between them. *
O 11 N
O 8 N
9.8 N
O 6.8 N​
Mathematics
1 answer:
bezimeni [28]3 years ago
5 0

Answer:its 11n

Step-by-step explanation:

Simple divide all

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Jason is the captain of his basketball team the list below shows how many points Jason scored in each of the first 10 games 18,2
Anika [276]
A. The scores in order are: 10, 12, 13, 14, 14, 16, 18, 23, 24, 26. The range is 26 - 10 = 16. The mean is the sum divided by 10, which is 17. The median is between 14 & 16, which is 15. The mode is 14, since it is repeated twice.
B. The variance is calculated by subtracting each score from the mean, squaring, and adding all such squares. Then divide by the number of terms (10) to get 27.6 Take the square root to get the standard deviation, which is 5.25.
C. This is for a population, since these are all 10 games that Jason played. (If it were a sample, we would divide by 9 only)

D. The mean of 17 is higher than the median of 15 and the mode of 14. This implies a left-skewed distribution. However, the SD of 5.25 is quite high relative to the mean of 17, so the distribution is not that clearly defined yet (more data points would make it clearer).
4 0
3 years ago
Which list orders the numbers from least to greatest
DENIUS [597]
The second line
least to greatest: -3, -2.4, -21/4, -1.5, -11/8
5 0
2 years ago
Andre rode his bike at a constant speed. He rode 1 mile in 5 minutes.
Anna71 [15]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Do you think x and x by the power of 2 are like terms? Explain using words, diagrams, tables etc.
natali 33 [55]

Answer:

No

Step-by-step explanation:

No, because x + x^2 cannot be grouped together.

8 0
3 years ago
Find the area of the semicircle. diameter = 12
dimaraw [331]

Answer:

\huge\boxed{\sf Area\ of \ Semicircle = 56.55 \ units^2}

Step-by-step explanation:

Diameter = 12

Radius = 12/2 = 6

\sf Area\ of \ Semicircle =\frac{\pi r^2}{2} \\Area\ of \ Semicircle =\frac{\pi (6)^2}{2} \\Area \ of \ Semicircle = \frac{\pi (36)}{2}\\ Area \ of \ Semicircle = 18 \ pi

\sf Area\ of \ Semicircle = 56.55 \ units^2

7 0
3 years ago
Read 2 more answers
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