Last month, a shop had 3200 customers.

1) What is the GCF for the polynomial 4x3 - 2x2y?

Dafna1 [17]

(1)the GCF for the polynomial $4x^3 - 2x^2y$

4x^3 = 2*2* x* x* x

2x^2y = 2*x*x*y

Greatest common factor is $2*x*x = 2x^2$

(2) the GCF for the polynomial $8x^4y + 6x^2y^2$

$8x^4y = 2*2*2*x*x*x*x*y$

$6x^2y^2 = 3*2*x*x*y*y$

GCF is $2*x*x*y=2x^2y$

(3) the GCF for the polynomial $12x^3y^2 - 20x^5y^3$

$12x^3y^2 = 2*2*3*x*x*x*y*y$

$20x^5y^3=5*2*2*x*x*x*x*x*y*y*y$

GCF is $2*2*x*x*x*y*y= 4x^3y^2$

(4) the GCF for the polynomial $-10x^3y^4 - 16x^5y^2$

$-10x^3y^4 =-2*5*x*x*x*y*y*y*y$

$-16x^5y^2=-2*2*2*2*x*x*x*x*x*y*y$

GCF is $-2*x*x*x*y*y= -2x^3y^2$

3 0

3 years ago

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The radius of the tires of a car is 18 inches, and they are revolving at the rate of 651 revolutions per minute. How fast is the

Mumz [18]

So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches

so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"

now, what's the linear velocity, namely, the arc covered per minute

well $\bf v=rw\qquad 
\begin{cases}
v=\textit{linear velocity}\\
r=radius\\
w=\textit{angular velocity}\\
----------\\
r=18in\\
w=1302\frac{\pi }{min}
\end{cases}\implies v=18in\cdot \cfrac{1302\pi }{min}
\\\\\\
v=\cfrac{23436\pi\ in}{min}$

now, how much is that in miles/hrs? well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr

thus $\bf \cfrac{23436\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mi}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{23436\cdot \pi \cdot 60\ mi}{12\cdot 5280\ hr}$

notice, after all the units cancellations, you're only left with mi/hrs

4 0

3 years ago

Triangle RST has vertices R(2, 0), S(4, 0), and T(1, –3). The image of triangle RST after a rotation has vertices

velikii [3]

<span>C) Ro 270 degree (anticlockwise)

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6 0

4 years ago

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Simora [160]

The limit does not exist. There are infinitely many infinite discontinuities at $x=n\pi$ , where $n\in\Bbb N$ . The function oscillates wildly between negative and positive infinity.

5 0

2 years ago

What is the area of the sector? Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi and enter

n200080 [17]

Question:

What is the area of the sector? Either enter an exact answer in terms of π or use 3.14 and enter your answer as a decimal rounded to the nearest hundredth.

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the values of radius and central angle are not given.

However, I'll answer the question using the attached figure.

From the attached figure, the radius is 3 unit and the central angle is 120 degrees

The area of a sector is calculated as thus;

$Area = \frac{\alpha }{360} * \pi r^2$