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Yanka [14]
2 years ago
10

Help...................

Mathematics
1 answer:
qaws [65]2 years ago
7 0
I Dont know the answer
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Find the lateral area of the prism.<br> 4cm<br> 3cm <br> 6cm<br> 5cm<br> Lateral Area = [?]cm2
kolbaska11 [484]

Answer:

The lateral surface area of a prism is the sum of the surface areas of the sides of the prism.

Since the bases of the prism are triangles, there are three sides. The area of each lateral is the product of a side of the triangle times the height of the prism.

We can express this as Lateral Surface Area LSA = (s1xh) + (s2xh) + (s3+h), where "s1, s2, s3" are the lengths of the sides of the triangle and "h" is the height of the prism.

We can factor out "h" to get LSA = hx(s1+s2+s3) where the factor "s1+s2+s3" is the perimeter of the triangle.

Solving for "h", we get h = LSA / (s1+s2+s3)

For your specific problem, h = 300 / (4 + 5 + 6) = 300 / 15 = 20

4 0
2 years ago
Plase help me I already set the equation up I just need you to solve it.
masya89 [10]

\sf \frac{6}{30}  =  \frac{x}{100}

Solve for x by cross multiplication

\sf6 \times 100 = x \times 30

  • Multiply the numbers

\sf \: 600 = 30x

  • Swap the sides of equation

\sf \: 30x = 600

  • Divide both sides of equation by 30

\boxed{ \tt \: x = 20}

3 0
3 years ago
Read 2 more answers
Larry rolls 2 fair dice and adds the results from each.
aksik [14]

Answer:

5/36

Step-by-step explanation:

Dice 1 cannot be 1 no matter how large dice 2 gets

Dice 1 = 2,3,4,5,6 each matches with dice 2 to get a sum of 8

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B1150%3F%20%7D%20%20%3D%20" id="TexFormula1" title=" \sqrt[5]{1150? } = "
zimovet [89]
=4.0939
If you only need 1 d.p then it’s 4.1
3 0
2 years ago
· Eight times the difference of a number and 3 is 40.
defon

Answer:

The number is 8

Step-by-step explanation:

equation:

8*(x-3) = 40

8x - 24 = 40

8x = 64

x = 8

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 0
3 years ago
Read 2 more answers
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