The range is the set of values that the relation takes for the domain for which it is defined.
Is the set of values of the dependent variable.
In this case, we have the relation [(-5,0),(-4,-3),(-3,4),(-1,0),(-4,-1)].
The dependant variable takes the values: 0, -3, 4, 0 and -1. Some values are repeated.
We put the repeated values only once and sort to write the range.
Then, the range is R = {-3, -1, 0, 4}.
Answer: Range = {-3, -1, 0, 4}
A.) Since there are no restrictions as to the dimensions of the candle except that their volumes must equal 1 cubic foot and that each must be a cylinder, we have the freedom to decide the candles' dimensions.
I decided to have the candles equal in volume. So, 1 cubic foot divided by 8 gives us 0.125 cubic foot, 216 in cubic inches.
With each candle having a volume of 216 cubic inches, I assign a radius to each: 0.5 in, 1.0 in, 1.5 in, 2.0 in, 2.5 in, 3.0 in, 3.5 in, and 4.0 in. Then, using the formula of the volume of a cylinder, which is:
V=pi(r^2)(h)
we then solve the corresponding height per candle. Let us let the value of pi be 3.14.
Hence, we will have the following heights (expressed to the nearest hundredths) for each of the radius: for
r=2.5 in: h=11.01 in
r=3.0 in: h= 7.64 in
r=3.5 in: h= 5.62 in
r=4.0 in: h= 4.30 in
r=4.5 in: h= 3.40 in
r=5.0 in: h= 2.75 in
r=5.5 in: h= 2.27 in
r=6.0 in: h= 1.91 in
b. each candle should sell for $15.00 each
($20+$100)/8=$15.00
c. yes, because the candles are priced according to the volume of wax used to make them, which in this case, is just the same for all sizes
Answer:
Step-by-step explanation:
The original price for one lunch special is $19.
<em><u>Explanation</u></em>
The original price for one lunch special is 'p' dollar.
He wins a coupon for $4 off for each of five days. That means , <u>he needs to pay 
dollar each day</u>.
So, the total amount needed to pay for 5 days 
dollar
Given that, <u>he pays $75 for his 5 lunch specials</u>. So the equation will be.....
So, the original price for one lunch special is $19.
