Yes I agree with the last person, it’s Line D.
Answer:
You can reject the null at the 10% and 5% level of significance, but cannot reject the null at the 2%, or 1% level of significance. ( D )
Step-by-step explanation:
let : P = 0.6
x = 135 , n = 200
<em>p </em>= 135 / 200 = 0.675
H0 : P = 0.6
Ha : P ≠ 0.6
performing the test statistic = ( 0.675 - 0.6 ) / 
= 0.075 / 0.0346 ≈ 2.17
p-value = 2 * P ( Z > - 2.17 ) ( using excel function ; NORMSDIST )
= 2 * 0.015 = 0.03
Answer:
no its x = - 4
Step-by-step explanation:
For the expression to be factor-able the Discriminant , has to be greater or equal to zero
ax^2 + cx + b = 0
c^2 - 4 ab >= 0
(-3)^2 - 4 * 1 * b >= 0
9 - 4b >= 0
9 >= 4b
b <= 9/4 (2.25)
Pick any value in that range for ex:
0 , 2, -3, -6
Answer:
$328.12
Step-by-step explanation:
8.75X37.5