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Diano4ka-milaya [45]
3 years ago
13

How is solving −5x = −6.5 different from solving − 1 5 x = −6.5? How are the solutions related? Complete the explanation.

Mathematics
2 answers:
slega [8]3 years ago
4 0

Answer:

hello, i just wanna say no one is gonna answer any of your questions :))

Alexxandr [17]3 years ago
3 0

Answer:

Step-by-step explanation:

uhedguiahfig;ahihgijah;oi

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What’s the surface area
DerKrebs [107]

Answer:

54

Step-by-step explanation:

7 0
2 years ago
Erin bought a $205 smart phone, but her total was $217.30. What percent sales tax did she pay?
andrey2020 [161]

Answer:

6.00 %

Step-by-step explanation:

205.00 × 0.060= 12.3

205.00 + 12.3= $217.30

6 0
2 years ago
2w^2-11w=-12 <br> a w=3/2 or 4<br> b w=1 or 12<br> c w=1 or 7<br> d w = 2.5 or 6
dlinn [17]
Hey mate !!
Here's your answer !!


2w^2 - 11w = -12
2w^2 -11w + 12 = 0
2w^2 - 8w - 3w + 12 = 0

2w ( w - 4) -3 ( w - 4) = 0
(2w - 3) ( w - 4) = 0

Hence

2w - 3 = 0
2w = 3
w = 3/2

w - 4 = 0
w = 4

Hence value of w are 4 and 3/2

Hope this helps!!
Cheers!!
7 0
3 years ago
Can u please help me with this 2 problem please
Mice21 [21]
<h2>19.</h2><h3>Given</h3>
  • window width and height are in proportion to building width and height
  • window width and height are 11 in and 18 in, respectively
  • building height is 108 ft
<h3>Find</h3>
  • building width
<h3>Solution</h3>

The proportional relation can be written as

... (building width)/(building height) = (window width)/(window height)

Multiplying by (building height) gives

... (building width) = (building heigh) × (window width)/(window height)

... (building width) = 108 ft × (11 in)/(18 in)

... building width = 66 ft

<h2>21.</h2><h3>Given</h3>
  • map distance = 6.75 in
  • map scale = 1.5 in : 5 mi
<h3>Find</h3>
  • actual distance
<h3>Solution</h3>

The distances are in proportion, so

... (map distance) : (actual distance) = 1.5 in : 5 mi

Multiplying by (5 mi)/(1.5 in)×(actual distance), we have

... (5 mi)/(1.5 in)×(6.75 in) = (actual distance) = 22.5 mi

6 0
3 years ago
It takes 24 megabytes to store 144 songs on a music player. What is the greatest number of songs that 60 megabytes could store?
givi [52]

Option B

We can store a total of 360 songs in 60 megabytes of space.

<u>Solution:</u>

It is given to us that It takes 24 megabytes to store 144 songs on a music player. We have been asked to find out what is the greatest number of songs that 60 megabytes could store.

To solve this question we can use the unitary method.  

We will first find out how many songs can be stored in 1 megabyte. This can be done as follows:

=\frac{144}{24}=6

Therefore, we can store 6 songs in 1 megabyte.

So, in 60 megabyte we can store the following number of songs:

=60 \times 6=360

So, we can store a total of 360 songs in 60 megabytes.

8 0
3 years ago
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