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DochEvi [55]
2 years ago
15

Can somebody plz help give the correct equations for both of the word problems (only if u done this before) thx :D

Mathematics
2 answers:
fgiga [73]2 years ago
4 0

Answer:

A. 12 cm

B. brent scored 9

HOPE THIS HELPS YOU

BlackZzzverrR [31]2 years ago
4 0

1. h = b + 5

when b = 7,

h = 7 + 5

=> h = 12

2. o = 4b

when o = 36,

36 = 4b

=> 36/4 = b

=> 9 = b

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What is the surface area of cone below Diameter AB=21 and distance from B to C =36
Vesnalui [34]

Answer:

1533.88261311522

Step-by-step explanation:

<em>Let r be the radius of the (base/circle)</em>

<em>and  L be the slant height of the cone</em>

<em>Formula ………………………………………………………………………………………………………</em>

The surface area of a cone = the (curved/lateral) surface area +  the base

                                             =\pi r^{2}\ \ \ +\ \ \ \pi Lr

=========================================

r=\frac{21}{2} =10.5

L = BC = 36

\text{surface area} =\pi \left( 10.5\right)^{2}  +\pi \times 36\times \left( 10.5\right)

                   =346.360590058275 + 1187.52202305694

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6 0
1 year ago
Simplify the expression 288 · 1318 − 288 · 1316.
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Step-by-step explanation:

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3 years ago
Construct a tangent to the circle at point B.<br><br> PLEASE HELP!!
Serga [27]

Answer:

you do a line that goes through b but doesn't go through the circle

3 0
3 years ago
(4 + 32)(15 – 23)<br> can someone help me out with the answer? :,)
hoa [83]

Answer:

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Step-by-step explanation: I took the following steps to find the answer:

(4 + 32)(15 – 23)

\             /

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           \          /

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4 0
2 years ago
Which of the following is an improper integral?
guapka [62]

Answer:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

General Formulas and Concepts:

<u>Calculus</u>

Discontinuities

  • Removable (Hole)
  • Jump
  • Infinite (Asymptote)

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C
  • Improper Integrals

Step-by-step explanation:

Let's define our answer choices:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

B)  \displaystyle \int\limits^3_1 {\frac{x + 1}{3x - 2}} \, dx

C)  \displaystyle \int\limits^0_{-1} {\frac{x + 1}{3x - 2}} \, dx

D) None of these

We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.

Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.

∴ our answer is A.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Integration

Book: College Calculus 10e

6 0
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