Answer:
Step-by-step explanation:
I am assuming the tank starts empty. It means that in 1 hour the tank has half that water, or 3600 gallons. And the good thing of lines passing through 0.0 is that the value at 1 IS the slope we need. ie 3600.
At this point it's easy to find that if in 2 hours it filled 1/10th of the tank, in 20 hours the tank will be full.
Graph done with paint, obviously not to scale.
Answer:
f^-1(x) = x - 2
Step-by-step explanation:
To find the inverse of a function in terms of x and y, you would sway x and y in the function. We can rewrite f(x) = x + 2 as y = x + 2, since f(x) is basically y in a function. The inverse of y = x + 2 would be x = y + 2. Now, solve for y.
x = y + 2
-2 both sides.
x - 2 = y
y = x - 2
The inverse of y = x + 2 would be y = x - 2, so the inverse of f(x) = x + 2 would be f^-1(x) = x - 2 (f^-1(x) means the inverse of f(x)).
f^-1(x) = x - 2
I hope you find this helpful. :)
First, convert the equation to the standard equation of a parabola.
-1/4(y+4)=(x-3)^2 ---multiply -4 on both sides
y+4=-4(x-3)^2 ---subtract 4 on both sides
y=-4(x-3)^2-4
From the equation, we know that the parabola was moved by 3 to the right, because of (x-3)^2. So the axis of symmetry is x=3. Now look at the number in front of (x-3)^2. It is -4. Since it is negative, the parabola opens downwards.
10 = 2y + 4
6 = 2y
y = 3
18 = 10 + 2x
8 = 2x
x = 4
The percentage of young adults send between 128 and 158 text messages per day is; 34%
<h3>How to find the percentage from z-score?</h3>
The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.
We are given;
Sample mean; x' = 158
Population mean; μ = 128
standard deviation; σ = 30
We want to find the area under the curve from x = 248 to x = 158.
where x is the number of text messages sent per day.
To find P(158 < x < 248), we will convert the score x = 158 to its corresponding z score as;
z = (x - μ)/σ
z = (158 - 128)/30
z = 30/30
z = 1
This tells us that the score x = 158 is exactly one standard deviation above the mean μ = 128.
From online p-value from z-score calculator, we have;
P-value = 0.34134 = 34%
Approximately 34% of the the population sends between 128 and 158 text messages per day.
Read more about p-value from z-score at; brainly.com/question/25638875
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