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Grace [21]
3 years ago
15

Find the fifth term of the arithmetic sequence in which

Mathematics
1 answer:
DerKrebs [107]3 years ago
4 0
We have given t_{1}=3 and t_{n} =  t_{n-1} + 4. Fifth term is t_{5}= t_{4}+4. It means we need to find t_{4} and in order to find the latter, we have to find t_{4}= t_{3}+4, t_{3}= t_{2}+4 and t_{2}= t_{1}+4 . Since we know the value of  t_{1}, beginning from the last equation we can find the value of  t_{5}. We can write that t_{2}= t_{1}+4=3+4=7, t_{3}= t_{2}+4=7+4=11 and t_{4}= t_{3}+4=11+4=15. Since t_{5}= t_{4}+4, then t_{5}= 15+4=19
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I need help on number 7
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The answer is c, he read 3/5 of the book on Monday and Tuesday.
4 0
2 years ago
Identify the expression which represents the calculation “subtract 3 from 15, then divided by 6
matrenka [14]

Answer:

\frac{15-3}{6}

Step-by-step explanation:

You would start by writing the expression for “subtract 3 from 15", which would be \frac{15-3}{6}, then you would add on "then divided by 6", which would make it

4 0
2 years ago
Read 2 more answers
Use Heron's formula to find the area of the triangle. Round to the nearest square foot.
Sphinxa [80]

Answer:

A ≈ 2 ft²

Step-by-step explanation:

The area (A) of a triangle using Heron's formula is

A = \sqrt{s(s-a)(s-b)(s-c)}

where s is the semiperimeter and a, b , c the sides of the triangle.

s = \frac{a+b+c}{2} = \frac{4+4+1}{2} = \frac{9}{2} = 4.5

Then

A = \sqrt{4.5(4.5-4)(4.5-4)(4.5-1)}

   = \sqrt{4.5(0.5)(0.5)(3.5)}

   = \sqrt{3.9375}

   ≈ 1.9843...

   = 2 ft² ( to the nearest square foot )

8 0
2 years ago
500th term of 24,31,38,45,52
tensa zangetsu [6.8K]
This looks like a simple arithmetic series. Each term is 7 greater than the previous term.

Therefore, the Nth term is 17 + 7N. 

For example, the first term is 17 + 7*1 = 17 + 7 = 24.

The second term is 17 + 7*2 = 17 + 14 = 31

etc...

And the 500th term is 17 + 7 * 500 = 17 + 3500 = 3517
3 0
3 years ago
a polygon has an area of 225 square meters. A similar polygon is created with an area that is triple the first. By what factor i
GuDViN [60]
The area of the original polygon is:
 A = 225 m ^ 2
 The similar polygon area is:
 A '= (k ^ 2) * (A)
 Substituting values:
 3 * 225 = (k ^ 2) * (225)
 Clearing k we have:
 k ^ 2 = 3
 k = (3) ^ (1/3)
 Answer:
 
The length of each side increased by:
 
k = (3) ^ (1/3)
6 0
3 years ago
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