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3 years ago

Write the repeating decimal number as a mixed number?

Mathematics

1 answer:

Akimi4 [234]3 years ago

7 0

Answer:

2 1111/10000

maybe, i tryed sorry if its not correct

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The solution of the given system of linear equations will lie in which of the following quadrants?

Rashid [163]

Answer: C Fourth Quadrant

Step-by-step explanation:

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4 years ago

In the first two hockey games of the year, Rodayo played 1 1/2 periods and 1 3/4 periods. How many periods in all did he play? P

Talja [164]

Answer:

Rodayo played 3 1/4 periods in all

Step-by-step explanation:

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3 years ago

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A new bank costumer with 2500 dollars wants to open a money market account. The bank is offering a simple interest rate of 1.5 p

padilas [110]

Answer:

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

I represents interest paid on the amount deposited.

P represents the principal or amount deposited.

R represents interest rate

T represents the duration in years.

From the information given,

P = 2500

R = 1.5%

T = 30 years

I = (2500 × 1.5 × 30)/100 = $1125

the account balance be after 30 years is

1125 + 2500 = $3625

4 0

3 years ago

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What is the future value of 300000 with an interest rate of 17% per annum for 30 days?

Anvisha [2.4K]

$\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$300000\\
r=rate\to 17\%\to \frac{17}{100}\to &0.17\\
t=years\to \frac{30}{365}\to &\frac{6}{73}
\end{cases}
\\\\\\
A=300000\left(1+0.17\cdot \frac{6}{73}\right)$

3 0

3 years ago

ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)

Delicious77 [7]

$remember$
$ln(x)=log_e(x)$
$and$
$log_x(a)-log_x(b)= log_x( \frac{a}{b} )$
$and$
$log_a(b)=c$ means $a^c=b$
$and$
$blog(a)=log(a^b)$

$so$

$ln(y+1)-ln(y)=1+3ln(x)$
$ln( \frac{y+1}{y} )=1+ln(x^3)$

$minus$ $ln(x^3)$ $from$ $both$ $sides$

$ln( \frac{y+1}{y}-ln(x^3) )=1$
$ln( \frac{y+1}{yx^3})=1$
$log_e( \frac{y+1}{yx^3})=1$

$translate$

$e^1=\frac{y+1}{yx^3}$
$e=\frac{y+1}{yx^3}$

$times$ $both$ $sides$ $by$ $yx^3$

$eyx^3=y+1$

$minus$ $y$ $from$ $both$ $sides$

$eyx^3-y=1$
$y(ex^3-1)=1$

$divide$ $both$ $sides$ $by$ $(ex³-1)$

$y= \frac{1}{ex^3-1}$

6 0

3 years ago

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