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VARVARA [1.3K]
3 years ago
8

Write the repeating decimal number as a mixed number?

Mathematics
1 answer:
Akimi4 [234]3 years ago
7 0

Answer:

2 1111/10000

maybe, i tryed sorry if its not correct

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The solution of the given system of linear equations will lie in which of the following quadrants?
Rashid [163]

Answer: C Fourth Quadrant

Step-by-step explanation:

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4 years ago
In the first two hockey games of the year, Rodayo played 1 1/2 periods and 1 3/4 periods. How many periods in all did he play? P
Talja [164]

Answer:

Rodayo played 3 1/4 periods in all

Step-by-step explanation:

7 0
3 years ago
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A new bank costumer with 2500 dollars wants to open a money market account. The bank is offering a simple interest rate of 1.5 p
padilas [110]

Answer:

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

I represents interest paid on the amount deposited.

P represents the principal or amount deposited.

R represents interest rate

T represents the duration in years.

From the information given,

P = 2500

R = 1.5%

T = 30 years

I = (2500 × 1.5 × 30)/100 = $1125

the account balance be after 30 years is

1125 + 2500 = $3625

4 0
3 years ago
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What is the future value of 300000 with an interest rate of 17% per annum for 30 days?
Anvisha [2.4K]
\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$300000\\
r=rate\to 17\%\to \frac{17}{100}\to &0.17\\
t=years\to \frac{30}{365}\to &\frac{6}{73}
\end{cases}
\\\\\\
A=300000\left(1+0.17\cdot \frac{6}{73}\right)
3 0
3 years ago
ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)
Delicious77 [7]
remember
ln(x)=log_e(x)
and
log_x(a)-log_x(b)= log_x( \frac{a}{b} )
and
log_a(b)=c means a^c=b
and
blog(a)=log(a^b)



so

ln(y+1)-ln(y)=1+3ln(x)
ln( \frac{y+1}{y} )=1+ln(x^3)

minus ln(x^3) from both sides

ln( \frac{y+1}{y}-ln(x^3) )=1
ln( \frac{y+1}{yx^3})=1
log_e( \frac{y+1}{yx^3})=1

translate

e^1=\frac{y+1}{yx^3}
e=\frac{y+1}{yx^3}

times both sides by yx^3

eyx^3=y+1

minus y from both sides

eyx^3-y=1
y(ex^3-1)=1

divide both sides by (ex³-1)

y= \frac{1}{ex^3-1}
6 0
3 years ago
Read 2 more answers
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