Rational because 5^3
irrational
Answer:
it's parabola
Step-by-step explanation:
don't worry I did my research on this one:)
17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
Answer: y=3x-7
Explanation:
The y-intercept is -7 and the line is going up by a rate of 3.
Answer:
Hello! Here is your answer
Step-by-step explanation:
112=4(28)
a=4b
You can only have one variable so:
Combine b to a:
a-b=84
4b-b=84
Divide both sides by 3:
3b/3=84/3
b=28
But that is not it:
Sum of both cards:
a+b
a=112
b=28
112+28=140
= 140
I hope I was of help. If not please let me know! Thank you! Good luck!
