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2 years ago

Which statement correctly identifies a point on the graph of f–1(x)?

Mathematics

1 answer:

Black_prince [1.1K]2 years ago

7 0

Answer:

Step-by-step explanation:

I didn’t see any choices but an inverse function switches the x and y values.

For every (x,y) of f(x) the inverse function will have (y,x) of f^-1(x)

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What is 68 percent of 575?

Travka [436]

Answer:

391

Step-by-step explanation:

First you must make the fraction a decimal so you can use it in an equation.

To do so move the . over to the left twice.

.68

Now multiply 575 by .68

575 x .68=391

7 0

2 years ago

Read 2 more answers

How do you put 943,261,586 with base ten numbers

Citrus2011 [14]

Answer:

(9 $\times$ $10^{8}$ ) + (4 $\times$ $10^{7}$ ) + (3 $\times$ $10^{6}$ ) + (2 $\times$ $10^{5}$ ) + (6 $\times$ $10^{4}$ ) + ( $10^{3}$ ) + (5 $\times$ $10^{2}$ ) + (8 $\times$ 10) + (6 $\times$ $10^{0}$ )

Step-by-step explanation:

How do you put 943,261,586 with base ten numbers

943,261,586 =

900,000,000 + 40,000,000 + 3,000,000 + 200,000 + 60,000 + 1,000 + 500 + 80 +6 =

8 0

2 years ago

Monique made several batches of soup for a potluck supper. Each batch required 3\4 0f a pound of potatoes, and she used a total

eimsori [14]

Answer:

$The\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ \frac{26}{3}.$

$The\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ 8.67 (Approx).$

Step-by-step explanation:

As given

$Monique\ made\ several\ batches\ of\ soup\ for\ a\ potluck\ supper.$

$Each\ batch\ required\ \frac{3}{4}\ of\ a\ pound\ of\ potatoes.$

$she\ used\ a\ total\ of\ 6 \frac{1}{2}\ pounds\ of\ potatoes.$

As given the expression.

$= \frac{6 \frac{1}{2}}{\frac{3}{4}}$

$= \frac{\frac{13}{2}}{\frac{3}{4}}$

Solving the above

$= \frac{13\times 4}{2\times 3}$

$= \frac{26}{3}$

In the decimal form.

= 8.67 (Approx)

$Therefore\ the\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ \frac{26}{3}.$

$Therefore\ the\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ 8.67 (Approx).$

6 0

2 years ago

1. Solve the following system of equations, using matrix inversion method.

Jet001 [13]

Answer:

x = 142/83

y = 111/83

z = 452/83

8 0

2 years ago

Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.

Leya [2.2K]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6$

6 0

2 years ago