The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
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Answer:
-6/-2=3 (the answer is 3)
Step-by-step explanation:
Change in y/ Change in x. How you do it: -6-0/2-4=-6/-2=3
Hope this helped :)
Answer:
finger it out
Step-by-step explanation:
5/6 % 1/2 you flip the 1 and 2 so it will look like 2/1 then you multiply the fractions together
5/6 % 2 you make the 2 a frustration like 1/2 then you multiply 5/6 and 1/2 together
Df = g - 10
To solve for d, divide both sides by f.
df / f = (g - 10) / f
d = (g - 10) / f
I hope this explains it.
Answer:
3
3
5
2
Step-by-step explanation:
What kind of math is this and what grade are you in?
