Answer:
96
Step-by-step explanation
4(x - 2)(x + 3) + 7(x - 2)(x - 5) - 6(x - 3)(x - 5)
4(5 - 2)(5 + 3) = 12(8) = 96
7(5 - 2)(5 - 5) = 0
- 6(5 - 3)(5 - 5)= 0
96+0-0 = 96
Answer:
The probability that a ship that is declared defecive is sound is 0.375
Step-by-step explanation:
Let P(A|B) denote the conditional probability of A given B. We will make use of the equation
P(A|B) = P(A) × P(B|A) / P(B)
We have the probabilities:
- P(Declared Defective (detected) | Defective) = 0.95
- P(not Detected | Defective) = 1-0.95=0.05
- P(Declared Sound | Sound) = 0.97
- P(Declared Defective |Sound) = 1-0.97=0.03
We can calculate:
P(Declared Defective)= P(Detected | Defective)×P(Defective) + P(Declared Defective |Sound) ×P(Sound) = 0.95×0.05 + 0.03×0.95=0.076
P(S | Declared Defective) =
(P(Sound) × P(Declared Defective | Sound)) / P(Declared Defective)
=0.95×0.03 /0.076 =0.375
Answer:
use a calculator
Step-by-step explanation:
also if this is easier change 1/2 and 1/3 to 0.5 and 0.3 where it would be 8.5 x 3.3
Answer:
3/10
Step-by-step explanation:
To find how much remains, you need to find 1/2 of 3/5 which is 1/2 * 3/5. To multiply the two fractions, multiply the two numerators and multiply the two denominators to get 3/10. Thus, 3/10 of the candy bar remains.
Hope this helps :)
let's recall that d = rt, distance = rate * time.
he went upstream to a distance "d", got tired and came back to his starting point, so he rowed back a distance "d" exactly.
we know the rates, we also know the trip took 2 hours, let's say on the way over he took "t" hours to get there, on the way back he lasted then "2 - t" hours.
![\stackrel{\textit{substituting on the 2nd equation}}{2t=8(2-t)\implies 2t=16-8t}\implies 10t=16\implies t=\cfrac{16}{10}\implies t=\cfrac{8}{5} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{we know that}}{d=2t}\implies d=2\left( \cfrac{8}{5} \right)\implies \stackrel{\textit{3 miles and 1056 feet}}{d=\cfrac{16}{5}\implies d=3\frac{1}{5}}](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Bsubstituting%20on%20the%202nd%20equation%7D%7D%7B2t%3D8%282-t%29%5Cimplies%202t%3D16-8t%7D%5Cimplies%2010t%3D16%5Cimplies%20t%3D%5Ccfrac%7B16%7D%7B10%7D%5Cimplies%20t%3D%5Ccfrac%7B8%7D%7B5%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bwe%20know%20that%7D%7D%7Bd%3D2t%7D%5Cimplies%20d%3D2%5Cleft%28%20%5Ccfrac%7B8%7D%7B5%7D%20%5Cright%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7B3%20miles%20and%201056%20feet%7D%7D%7Bd%3D%5Ccfrac%7B16%7D%7B5%7D%5Cimplies%20d%3D3%5Cfrac%7B1%7D%7B5%7D%7D)
