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svetlana [45]
3 years ago
8

Find the surface area for the triangular prism below. Whoever answers right the quickest will get brainliest. PLEASE HELP QUICKL

Y!!!

Mathematics
1 answer:
LenKa [72]3 years ago
6 0

Answer:

To answer your question use the code ICE on here to get your answer works every time for me hope this helps

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Solve each equation.<br> 1. 25 - 3x = 40<br> 2. } (x – 10) = -4
nordsb [41]

Step-by-step explanation:

For no 1

<em>2</em><em>5</em><em> </em><em>-</em><em> </em><em>3x </em><em>=</em><em> </em><em>4</em><em>0</em><em> </em>

<em>-</em><em> </em><em>3x </em><em>=</em><em> </em><em>4</em><em>0</em><em> </em><em>-</em><em> </em><em>2</em><em>5</em><em> </em>

<em>-</em><em> </em><em>3x </em><em>=</em><em> </em><em>1</em><em>5</em><em> </em>

<em> </em><em>-</em><em> </em><em>x </em><em>=</em><em> </em><em>1</em><em>5</em><em> </em><em>/</em><em> </em><em>3</em>

<em>Therefore </em><em> </em><em>x </em><em>=</em><em> </em><em>-</em><em> </em><em>5</em><em> </em>

<em>Now </em><em>for </em><em>no. </em><em> </em><em>2</em>

<em>1</em><em>/</em><em>3</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>1</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em> </em><em>4</em><em> </em>

<em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>1</em><em>0</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em> </em><em>1</em><em>2</em><em> </em>

<em>x </em><em>=</em><em> </em><em>-</em><em> </em><em>1</em><em>2</em><em> </em><em>+</em><em> </em><em>1</em><em>0</em>

<em>Therefore </em><em> </em><em>x </em><em>=</em><em> </em><em>-</em><em> </em><em>2</em><em> </em>

<em>Hope </em><em>it </em><em>will </em><em>help </em><em>:</em><em>)</em>

6 0
3 years ago
Read 2 more answers
Can u help<br> me im in 6th grade and bad at math
AfilCa [17]

Step-by-step explanation:

I can help you im in 7th grade and im good with math.

5 0
3 years ago
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There is a rectangle with a length of 12.5x +5 and a width of 5 . What is the area of the triangle
krek1111 [17]
The answer would be 65
4 0
3 years ago
Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co
Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}

2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}

3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}

4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}

8)  ∫ tan^5 (x) sec(x)  dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x

6 0
3 years ago
What is the square root of 98/2
timurjin [86]

Answer:

7

Step-by-step explanation:

\sqrt{ \frac{98}{2} }  =  \sqrt{49 }  = 7

I hope it helped you

8 0
2 years ago
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