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3 years ago

10 in

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

5 0

The answer is 36in because that’s the pathagreom you need to use to find the answer

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The total cost C dollars, that a shop charges to print T shirts C = 45 + 7n , is the number of shirts ordered. Coach Dell paid 2

Lesechka [4]

Answer:

i think the answer is 23

Step-by-step explanation:

well the equation says c=45+7n so the total cost is 206 . i subtracted 45 from 206 leaving me with 161 then i divided that by 7 leaving me with 23

8 0

3 years ago

Which symbol correctly compares the two angles? pie/3 30° 3 O A.< O B. = O C. >

k0ka [10]

Answer:

Step-by-step explanation:

π / 3 is in radians.

Radian need to be converted into

degree ( ° ).

The value of in degree is 180°

π / 3 = 180 / 3 = 60°

60° > 30°

So,

( π / 3 ) > 30°

5 0

2 years ago

when Elena 's car moves forward such that each tire make one full rotation ,the car has traveled 72 inches .how many full rotati

Marat540 [252]

It will take 5 full rotations for Elena's car to travel ten yards

explanation: 10 yards=30 feet, and there are 12 inches in one foot. multiply 30 by 12. once you do that, you get 360. next, divide 360 by the 72 inches in each full rotation. 360/72=5. so the answer is 5 full rotations

6 0

2 years ago

5) Find the value of the term in the arithmetic sequence. (an = a1 + (n - 1)d) 11,

kvasek [131]

Answer:

139, I am sorry if I'm wrong

Step-by-step explanation:

a1=11; d=19-11=8

a17=11+(17-1)*8=11+128=139

6 0

3 years ago

Find all solutions of the equation: 2cos^2x-cosx=1

Art [367]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3166243

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Solve the trigonometric equation:

$\mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}$

Make a substitution:

$\mathsf{cos\,x=t\qquad (-1\le t\le 1)}$

and the equation becomes

$\mathsf{2t^2-t-1=0}$

Rewrite conveniently – t as + t – 2t, and then factor the left-hand side by grouping:

$\mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}$

Factor out 2t + 1:

$\mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}$

Substitute back for t = cos x:

$\begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}$

Therefore,

$\begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}$

where k is an integer.

Solution set:

$\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}$

I hope this helps. =)

3 0

3 years ago