Answer:
x = 23.78
.........................
Answer:
<h2>
min: 52</h2><h2>
max: 78</h2><h2>
median: 63</h2><h2>
lower quartile median: 54</h2><h2>
upper quartile median: 73</h2><h2>
interquartile range: 19</h2>
Step-by-step explanation:
the temperatures ordered from least to greatest
52, 53, 54, 54, 57, 62, 64, 69, 73, 73, 77, 78
the min is 52
the max is 78
median:
52, 53, 54, 54, 57, 62, 64, 69, 73, 73, 77, 78
(62+64)/2=126/2=63
thus the median is 63
now we don't include the median in finding the upper and lower quartile medians:
lower quartile median:
52, 53, 54, 54, 57, 62
54 (same #s no need to add up and divide by 2)
upper quartile median:
64, 69, 73, 73, 77, 78
73 (same #s no need to add up and divide by 2)
interquartile range is:
upper quartile median-lower quartile median:
73-54
19
and $\theta$ lies in $2^{\text{th}}$ quadrant.
where, $x-$ coordinate is negative, and $y-$ coordinate is positive
so it can't a.
now, cosine means, side adjacent over the hypotenuse, in Cartesian plane, that will be $x-$ coordinate over the distance from origin.
Assume the triangle , with base $2$ units and hypotenuse $\sqrt{29}$ and it's in second quadrant. (so )
now, the leftmost point on $x-$ axis is , obviously $(-2,0)$
and by Pythagoras theorem, we can find the perpendicular side, that will be $y^2=(\sqrt{29})^2-(2)^2\implies y=5$
so the coordinates of the upper vertex is $(-2,5)$, each point lying on this "ray" should have equal ratio of respective coordinates. i.e. $\frac25=\left|\frac xy\right| $
and it should lie on second quadrant, so $x<0 \, y>0$
Option d satisfies this.
Answer: 6
Step-by-step explanation: 12x+3=75
-3 -3
<u>12x</u>=<u>72</u>
12 12
x=6
It'll take Jasmine 5 days and she'll make a total of £405.