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Degger [83]
4 years ago
14

Eli takes a typing test and types all 300 words in 1/10 hour. He takes the test a second time and types the words in 1/12 hour.

Was he faster the 2nd attempt?
Mathematics
2 answers:
Katyanochek1 [597]4 years ago
4 0

Answer:

He types the words faster the second attempt.

Step-by-step explanation:

When Eli types the words in a shorter period of time, he is faster when writing the words for his typing test. We can model which period of time is shorter by the simple inequality-

1/12 (second attempt) < 1/10 (first attempt)

This is, in ratio to minutes, this inequality-

5 minutes <  6 minutes

This means Eli's time writing the second time is shorter, making it the faster time.

juin [17]4 years ago
3 0

Answer:

Eli is faster the 2nd attempt

Step-by-step explanation:

If you do 1 divided by 10 you get 0.1 and if you do 1 divided by 12 you get 0.08. 0.1 is bigger than 0.08.

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Answer:

<u>★</u><u> </u><u>Divisibility</u><u> </u><u>rule</u><u> </u><u>for</u><u> </u><u>3</u><u> </u><u>-</u>

If the sum of all the digits divisible by 3 then the number is divisible by 3.

Here, we take an example for better understanding -

<u>Example</u><u> </u><u>1</u><u> </u><u>-</u> 3525

Add up the digits - 3 + 5 + 2 + 5

→ 15

As, 15 is divisible by 3. So, 3525 is a factor of 3.

★<u> </u><u>Divisibility</u><u> rule</u><u> </u><u>for</u><u> </u><u>6</u><u> </u><u>-</u>

A number is to be divisible by 6 , if the number is also divisible by 2 and 3.

<u>Exampl</u><u>e</u><u> </u><u>2</u><u> </u><u>-</u> 132

Add up the digits = 1 + 3 + 2 = 6

As, 6 is divisible by 2 and it's also divisible by 3. Then, 132 is a factor of 6.

★ <u>Divisibility</u><u> rule</u><u> for</u><u> </u><u>9</u><u> </u><u>-</u>

If the sum of all the digits is divisible by 9 then the number is divisible by 9. Just like we'd in 3.

<u>Example</u><u> </u><u>3</u><u> </u><u>-</u> 1052

Add up the digits - 10 + 5 + 2 = 17

As, 17 is not divisible by 9. So, 1052 is also not divisible by 9.

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3 years ago
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Step-by-step explanation:

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3 years ago
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galina1969 [7]

Answer:

the common ratio is 0.98.

Step-by-step explanation:

A fish population in a lake decreases by 2% each year. We are asked to find the common ratio.

The decrease of population of fish 2% annually means the population becomes next year 100% - 2% = 98%

Therefore, the common ratio would be 98%. Upon converting 98 percent to a decimal we will get,

98% = \frac{98}{100}=0.98

Therefore, the common ratio or decay factor is 0.98.

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Answer:

m:-\frac{1}{3}

Step-by-step explanation:

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