All categories

2 years ago

Predictions for 2005?

Mathematics

2 answers:

Olin [163]2 years ago

5 0

Answer:

6500 millions

Step-by-step explanation:

Vilka [71]2 years ago

3 0

64-65 million , bc as you see in the chart, the numbers go up 4-5 million each time. hope my explanation made sense

You might be interested in

People enjoyed attending the concert in the park.

djyliett [7]

1428 would be for men and women

3 0

3 years ago

Read 2 more answers

The ratio of girls to boys in jame’s chorus is 2 to 4. If there are 25 girls in her chorus, how many boys are there ?

Brilliant_brown [7]

Answer:

There are 50 boys

Step-by-step explanation:

girls to boys - 2:4

so 25x2=50

3 0

3 years ago

Can somebody help me thank you

arsen [322]

Surface Area of the cylinder is: <span>384.85
Volume of the cylinder is: </span><span>538.78</span>

6 0

2 years ago

In a certain city of several million people, 7.7% of the adults are unemployed. If a random sample of 300 adults in this city is

Lilit [14]

Answer: 0.2643

Step-by-step explanation:

Given : The proportion of adults are unemployed : p=0.077

The sample size = 300

By suing normal approximation to the binomial , we have

$\mu=np=300\times0.077=23.1$

$\sigma=\sqrt{np(1-p)}=\sqrt{300\times0.077(1-0.077)}\\\\=4.61749932323\approx4.62$

Now, using formula $z=\dfrac{x-\mu}{\sigma}$ , the z-value corresponding to 26 will be :-

$z=\dfrac{26-23.1}{4.62}\approx0.63$

Using standard distribution table for z , we have

P-value= $P(z\geq0.63)=1-P(z$

$=1-0.7356527=0.2643473\approx0.2643$

Hence, the probability that at least 26 in the sample are unemployed =0.2643

6 0

3 years ago

Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.

natulia [17]

$\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k$

Divergence is easier to compute:

$\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}$

$\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}$

Curl is a bit more tedious. Denote by $D_t$ the differential operator, namely the derivative with respect to the variable $t$ . Then

$\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}$

$\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k$

$\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k$

5 0

3 years ago