I walked forward 5m, back 3m, then forward 7m what is my displacement
2 answers:
You might be interested in
Answer:
Ok, we have a system of equations:
6*x + 3*y = 6*x*y
2*x + 4*y = 5*x*y
First, we want to isolate one of the variables,
As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:
(6*x + 3*y)/(2*x + 4*y) = 6/5
now we isolate one off the variables:
6*x + 3*y = (6/5)*(2*x + 4*y) = (12/5)*x + (24/5)*y
x*(6 - 12/5) = y*(24/5 - 3)
x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y
Now we can replace it in the first equation:
6*x + 3*y = 6*x*y
6*(0.5*y) + 3*y = 6*(0.5*y)*y
3*y + 3*y = 3*y^2
3*y^2 - 6*y = 0
Now we can find the solutions of that quadratic equation as:
So we have two solutions
y = 0
y = 2.
Suppose that we select the solution y = 0
Then, using one of the equations we can find the value of x:
2*x + 4*0 = 5*x*0
2*x = 0
x = 0
(0, 0) is a solution
if we select the other solution, y = 2.
2*x + 4*2 = 5*x*2
2*x + 8 = 10*x
8 = (10 - 2)*x = 8x
x = 1.
(1, 2) is other solution
Answer:
AB and CD are parallel lines
Step-by-step explanation:
• Parallel lines have equal slopes
• The slopes of perpendicular lines are negative reciprocals
Calculate the slope m using the gradient formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
let (x₁, y₁ ) = A(1, 4) and (x₂, y₂ ) = B(3, 8)
m = =
= 2
let (x₁, y₁ ) = C(- 1, 6) and (x₂, y₂ ) = D(3, 14)
m = =
= 2
Since slope of AB and CD are equal then lines are parallel