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sdas [7]
3 years ago
8

I walked forward 5m, back 3m, then forward 7m what is my displacement

Mathematics
2 answers:
vladimir2022 [97]3 years ago
5 0

Answer:

9m

Step-by-step explanation:

5 - 3 + 7 = 9

Roman55 [17]3 years ago
3 0

Answer:

9m

Step-by-step explanation:

5 - 3 = 2 + 7 = 9

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Rotate triangle ABC 90° clockwise around the origin given the vertices A(1,3)B(-1,4)C(2,5) what are the new vertices for triangl
fgiga [73]

Answer:

A' = (3,-1)

B' = (4,1)

C' = (5,-2)

Step-by-step explanation:

Given

A = (1,3)

B = (-1,4)

C = (2,5)

Rotation: 90 degrees clockwise

Required

Determine A'B'C'

When a point P (x,y) is rotated 90 degrees in the clockwise direction, the new coordinates is: P' (y, -x).

So, we have:

A = (1,3)

B = (-1,4)

C = (2,5)

Becomes

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B' = (4,1)

C' = (5,-2)

3 0
3 years ago
Anyone good with algebra 2??
sweet [91]
A discontinuity is a point that cannot exist because the x-coordinate would cause a problem in the equation. If you have a polynomial in the denominator, you must find which values of x would cause the polynomial in the denominator to evaluate to zero. Since division by zero is undefined, that would cause a discontinuity.

Let's look at your function.

f(x) = \dfrac{x^2 - 16}{6x - 24}

x^2 - 16  is in the numerator. It is defined for every value of x. There is no problem there.

6x - 24  is in the denominator. This is a function defined for every value of x, but since it is in the denominator, we must exclude the x-value that would cause this polynomial to evaluate to zero.

We set it equal to zero and solve the equation for x.

6x - 24 = 0

6x = 24

x = 4

For x = 0, the denominator has a value of zero, so at this point there is a discontinuity in function f(x).

The answer is:

x \ne 4

6 0
3 years ago
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