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SSSSS [86.1K]
3 years ago
5

Hey does anyone know how to fix a computer that goes on and off. It is a Asus chromebook and putting it into recovery mode didn'

t work. Thank you!
Computers and Technology
2 answers:
irina [24]3 years ago
8 0

um just return itExplanation:

slega [8]3 years ago
5 0

Answer:

tell someone about it.

if its a school problem tell a teacher, they will most likely hand you a new computer.

and if not, ask your parents or whoever.

Explanation:

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Design a class named largeIntegers such that an object of this class can store an integer of any number of digits. Add operation
SpyIntel [72]

Answer:

Here the code is given as follows,

Explanation:

Code:

import java.util.Scanner;

//created class named largeintegers

class largeintegers{

   //class can hold a long number

   long number;

   //constructor to set number

  largeintegers(long number){

      this.number=number;

  }

  //getNumber method to get number

  long getNumber(){

      return number;

  }

  //below are some basic operations

  long addition(long num1,long num2){

       return num1+num2;

   }

   long subtract(long num1,long num2){

       return num1-num2;

   }

   long multiply(long num1,long num2){

       return num1*num2;

   }

   boolean compare(long num1,long num2)

   {

       return num1>num2;

   }

  public static void main(String[] args) {

      //declared to long numbers

      long number1,number2;

      //scanner class to take user input

      Scanner sc= new Scanner(System.in);

      //taking input numbers

      System.out.println("Enter a Number ");

      number1=sc.nextLong();

      System.out.println("Enter 2nd Number :");

      number2=sc.nextLong();

      //created two objects

      largeintegers object=new largeintegers(number1);

      largeintegers object2=new largeintegers(number2);

      //displaying two numbers

      System.out.println("Entered Numbers ");

      System.out.println(object.getNumber());

      System.out.println(object2.getNumber());

      //calling basic methods using created objects

      System.out.println("Some Operations on Given two Numbers ");

      System.out.println("Addition:"+object.addition(object.getNumber(), object2.getNumber()));

      System.out.println("Subtraction:"+object.subtract(object.getNumber(), object2.getNumber()));

      System.out.println("Multiplication:"+object.multiply(object.getNumber(), object2.getNumber()));

      System.out.println("Comparison:");

      if(object.compare(object.getNumber(), object2.getNumber())==true)

      {

          System.out.println("First Number is Greater than Second Number ");

      }

      else

      {

          System.out.println("Second Number is Greater than First Number ");

      }

      sc.close();

  }

}

Output:-

6 0
3 years ago
Handhed computer is otherwise called as<br> 1.laptop<br> 2.Notebook<br> 3.Palmtop
NikAS [45]

Answer:

personal digital assistants (PDAs)palmtop

3 0
3 years ago
Which is an example of a variable name written in camelcase?
stiv31 [10]

Answer: songName

-DoggyMan5

4 0
3 years ago
Read 2 more answers
Explain why it is important to continually evaluate long-term goals
lilavasa [31]
It is important to continually evaluate long term goals because one's life situation can change from day to day. For example, one can be without work for many months and despairing of ever getting work when finally conditions improve and work becomes available. Life is full of opportunities and sooner or later opportunities will arise so that whereas the long term situation looked economically bleak before, now it can improve significantly.
3 0
4 years ago
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To ac
Gekata [30.6K]

Answer:

# include <iostream>

#include<stdio.h>

using namespace std;

bool IsLeapYear(int y)

int main()

{

int y;

cout<<"Enter the Year to check Leap or Not"<<endl;

cin>>y;

IsLeapYear(int y);

getch();

}

bool IsLeapYear(int y)

{

if (y%4==0)

{

   if (y%100==0)

    {

         if (y%400==0 )

         {

          cout<"The year is leap Year";

         }

         else

         {

         cout<<" The year is not Leap Year";

         }

     }

     else

     {

     cout<<"The year is Leap Year" ;

     }

}    

else

{

cout<<"The year is not Leap Year";

}    

}

Explanation:

In this program a function has been defined named as IfLeapYear, to check that whether the entered year is leap year or not. An year taken as integer data type named as y to enter the year to check. If the year is divisible by 4 but not divisible by 100 is the leap year. If the year is divisible by 4, divisible by 100 and also divisible by 400 is the century year and is also the leap year.

To check all the statements, Nested if-else conditions has been used to check multiple requirements of the leap year.

6 0
3 years ago
Read 2 more answers
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