To find three numbers between -0.62 and -0.61 you will add a number in the hundredth place.
For the first problem, the answer is D, because every year, the graph goes down by about $4,500.
For problem two,
a. It's located in quadrant one because x and y are both positive (I've attached a graph with labeled quadrants for reference)
I'm unsure about b and c but I hope I helped with the others!
The answer is 12 because you have to subtract
32-20