The area of a rectangle is 72 square units. If its width is 4 units, find the length.

Annie plants 6 rows of small flowers bulbs in a garden she plants 132 bulbs in each row.how many bulbs does Annie plant?

andrew11 [14]

(792 bulbs) To answer this question one would multiply the number of rows times the number of bulbs 6 x132= ? to get the answer.

3 0

3 years ago

Read 2 more answers

Use distributive property to remove the parentheses. Simplify your answer as much as possible please.

slavikrds [6]

Answer:

28y^3 -35y^5

Step-by-step explanation:

= 7y^3(4) -7y^3(5y^2)

= 28y^3 -35y^5

_____

The applicable rule of exponents is ...

(y^a)(y^b) = y^(a+b)

7 0

2 years ago

write the slope-intercept form of the line that passes through the point (1,0) and is parallel to x-y=7. type your answer in the

Brilliant_brown [7]

Parallel lines have the same slope but different y intercepts.
turn x-y=7 into slope intercept form by isolating y which would be -y=-x+7
divide the equation by -1 in order to make y positive and you get y=x-7
So rewrite the equation with the same slope but this time solving for b
y=x+b
plug in your coordinates
0=1+b
subtract 1 from both sides
-1=b
so your equation would be
y=x-1

7 0

3 years ago

Read 2 more answers

When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio

disa [49]

Answer:

The Decision Rule

Fail to reject the null hypothesis

The conclusion

There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

The data is

Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

The level of significance $\alpha = 0.05$

Generally the null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

the alternative hypothesis is $H_a : \mu_1 - \mu_2 > 0$

Generally the sample mean for the age of cars is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
}{27}$

=> $\= x_1 = 5.56$

Generally the standard deviation of age of cars

$\sigma _1 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _1 = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }$

=> $\sigma _1 = 3.88$

Generally the sample mean for the age of taxi is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{8 +8 +0 + \cdots + 4
}{20}$

=> $\= x_2 = 5.85$

Generally the standard deviation of age of taxi

$\sigma _2 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _2 = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }$

=> $\sigma _2 = 2.83$

Generally the test statistics is mathematically represented as

$t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1} + \frac{\sigma^2_2}{n_2} } }$

=> $t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27} + \frac{(2.83)}{20} }}$

=> $t = -0.30$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 -2$

$df = 27 + 20 -2$

$df = 45$

From the t distribution table the $P(t > t )$ at the obtained degree of freedom = 45 is

$P(t > -0.30 ) = 0.61722067$

So the p-value is

$p-value = P(t > T) = 0.61722067$

From the obtained values we see that the p-value > $\alpha$ hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

5 0

3 years ago

Marla filled up her car's gas tank and then went on a trip. After she drove 329 miles, she filled her tank with 14 gallons of ga

romanna [79]

Answer:

23 1/2 miles per gallon

Step-by-step explanation:

We start with dividing 329 miles with 14 gallons because it asks to find the number of miles on each gallon of gas -

Miles

----------------------------- =

Each gallon of gas

329 ÷ 14 = 23 1/2 miles per gallon

6 0

3 years ago