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ioda
2 years ago
9

Which ratio is the same as 2/3

Mathematics
2 answers:
RoseWind [281]2 years ago
6 0
There are many but 4/6 is the same and many others like it
AURORKA [14]2 years ago
3 0

Answer:

4/6 8/12 16/24 32/48 etc.

Step-by-step explanation:

You might be interested in
Help needed!
Jet001 [13]

Answer:

  • 15 inches

Step-by-step explanation:

<u>The ratio of sides in 30º-60º-90º triangle is:</u>

  • a : b : c = 1 : √3 : 2

<u>If a is 5√3, the length of b is:</u>

  • b = a√3 = 5√3 *√3 = 5*3 = 15
7 0
2 years ago
Solve the inequality for u.<br> 24 Simplify your answer as much as possible.
Annette [7]

Answer:

hey i think you forgot to add the expression, would u mind adding the question :) thanks

Step-by-step explanation:

3 0
3 years ago
6 1⁄3 + 7 1⁄4 – 2 1⁄2 =
Korvikt [17]

Answer:

11 1/12

Step-by-step explanation:

6 1/3 = 19/3

7 1/4 = 29/4

2 1/2 = 5/2

19/3 + 29/4 - 5/2


We must find the LCM of 3, 4, and 2. This happens to be 12

3*4 = 12

4*3 = 12

2*6 = 12

Multiply each fraction by the factor that'll get it to 12.


19/3 * 4/4 = 76/12

29/4 * 3/3 = 87/12

5/2 * 6/6 = 30/12

Now go through the problem


76/12 + 87/12 - 30/12

76 + 87 = 163

163/12 - 30/12

163 - 30 = 133

133/12

Simplify

133/12 = 11.0833... or 11 1/12


Hope this helps.

6 0
3 years ago
Identify the coordinates of the point (3,-2), translated 5 units left and 6
kap26 [50]

Answer:

(- 2, 4 )

Step-by-step explanation:

A translation of 5 units left means subtract 5 from the original x- coordinate.

A translation of 6 units up means add 6 to the original y- coordinate.

Thus

(3, - 2 ) → (3- 5, - 2 + 6 ) → (- 2, 4 )

3 0
4 years ago
A mouse climbs up a well of 86 meters. It advances 14 meters during the night, but during the day it retreats 2. The mouse will
Deffense [45]

Step-by-step explanation:

we assume day and night are equally long.

and the mouse will start at night of day 1.

then, on day 2, it will first retreat 2 meters (during daylight) and then advance 14 meters (at night).

so, on every full day, the mouse will effectively advance 12 meters (-2 + 14 = 12).

with a starting value of 14 (the first night).

so, we are getting an arithmetic sequence

an = an-1 + c

c = 12 in our case.

a1 = 14

a2 = a1 + 12 = 14+12 = 26

a3 = a2 + 12 = a1 + 12 + 12 = 14 + 2×12 = 38

an = a1 + (n-1)×12 = 14 + 12(n-1)

at what n will it reach 86 ?

86 = 14 + 12(n-1) = 14 + 12n - 12 = 2 + 12n

84 = 12n

n = 7

so, on the 7th day the mouse will reach the surface (if we truly count the first starting night day 1 - this is up to your teacher, but I would).

7 0
2 years ago
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