he answer that you should get is
250+100c+400= y
Answer:
there are several methods to "solve a quadratic"
you can look them all up...
Graphing, factoring, completing the square, taking roots, quadratic formula are the common methods....
given the way you are asking the question I think that you are supposed to use the quadratic formula ..
please look at the image of the formula and
realize that you problem has
a=-1
b=2
c=6
just plug in those numbers into the formula and you will get the results in the "answer"
NOTE
is written as ix (
)
Step-by-step explanation:
x= <u>-2+√ (2)²- (4)(-1)(-6) </u>
(2)(-1)
and
x= <u>-2-√ (2)²- (4)(-1)(-6) </u>
(2)(-1)
I need help tooooo cause at this point it’s frustrating me
Answer:
There are 12 bills of 10$ and 11 bills of 20$
Step-by-step explanation:
Let
x ------> number of 10$ bills
y -----> number of 20$ bills
we know that
x+y=23 -----> x=23-y -----> equation A
10x+20y=340 ----> equation B
substitute equation A in equation B and solve for y
10(23-y)+20y=340
230-10y+20y=340
10y=340-230
y=110/10=11
Find the value of x
x=23-y ----> x=23-11=12
therefore
There are 12 bills of 10$ and 11 bills of 20$