All categories

3 years ago

What is the product of (2x+1) and (3x+1) ?

1 answer:

8 0

A special trick to solve this is using a method called FOIL
It tells you what terms to multiply
F= first two terms
O= The outer terms
I= The two inside terms
L= The two last terms

(2x+1)(3x+1)
Multiply 2x and 3x
6x²
Then 2x and 1
2x
Next 1 and 3x
3x
Lastly, multiply 1 and 1
1
You get an equation that looks like this
6x² + 3x +2x +1
Combine 3x and 2x because they are like terms
YOUR FINAL ANSWER = 6x² + 5x + 1
You can use the FOIL method for all problems like this

You might be interested in

What is the equation in point-slope form of a line that passes through the points(-2,4) and has a slope if 5

Lelechka [254]

Answer:

Step-by-step explanation:it’s up two and left 4 and do that equation 5 times

5 0

3 years ago

A red container has 18 marbles. 5 of the marbles are black. Rest of the marbles are white and red. What additional information i

AveGali [126]

Your answer will be:

The total number of marbles that are not black.

7 0

3 years ago

Read 2 more answers

A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat

konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles

First, we need to find b:

$a^{2} + b^{2} = h^{2}$ (1)

$b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles$

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

$\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})$

$2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:

$0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

$\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h$

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0

3 years ago

At how many points does the graph of the function below intersect the x axis? y= 16x2 - 8x+1

Radda [10]

Y= 16x2 - 8x+1 does not intersect the c axis. It only peaks at it. The parabola does not go over it.

5 0

3 years ago

Read 2 more answers

A rectangle has a length of 19 in and a height of 11 in. Another rectangle has a length of 95

scoundrel [369]

Answer:

Option D. No,they are not similar because their side lengths are not proportional.

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem If the rectangles are similar

then

The ratio of its corresponding lengths must be equal to the ratio of its corresponding heights

Verify

$\frac{95}{19}=\frac{6.5}{11}\\\\95*11=19*6.5\\\\1,045\neq123.5$

therefore

The rectangles are not similar because their side lengths are not proportional.

4 0

3 years ago