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Radda [10]
2 years ago
9

At how many points does the graph of the function below intersect the x axis? y= 16x2 - 8x+1

Mathematics
2 answers:
Radda [10]2 years ago
5 0
Y= 16x2 - 8x+1 does not intersect the c axis. It only peaks at it. The parabola does not go over it.
BartSMP [9]2 years ago
5 0
The vertex of the parabola occurs at (1/4, 0) or (0.25, 0). Since the coefficient of x^2 is a positive number, then it the parabola opens upward. The vertex is the minimum point on the graph, which happens to occur along the x-axis at (1/4, 0) as the only x-intercept.

Therefore, the graph intersects the x-axis only once, at the vertex.

Please mark my answers as the Brainliest if you find this helpful :)
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andrew-mc [135]
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8 0
3 years ago
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Vesnalui [34]

Answer:

Option B. x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

14x^{2}+9x+10=0

so

a=14\\b=9\\c=10

substitute in the formula

x=\frac{-9(+/-)\sqrt{9^{2}-4(14)(10)}} {2(14)}

x=\frac{-9(+/-)\sqrt{-479}} {28}

Remember that

i=\sqrt{-1}

substitute

x=\frac{-9(+/-)\sqrt{479}i} {28}  

x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

5 0
3 years ago
DEAR SIRS AND MISSES, PLEASE HELP ME!
GaryK [48]
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4 0
3 years ago
What is the decimal form of 4 and 7/8
CaHeK987 [17]
4=   4.0

7/8=  <span>0.875

Hope this helped!

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8 0
3 years ago
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nignag [31]

Answer:

15

Step-by-step explanation:

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4 0
2 years ago
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