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Radda [10]
2 years ago
9

At how many points does the graph of the function below intersect the x axis? y= 16x2 - 8x+1

Mathematics
2 answers:
Radda [10]2 years ago
5 0
Y= 16x2 - 8x+1 does not intersect the c axis. It only peaks at it. The parabola does not go over it.
BartSMP [9]2 years ago
5 0
The vertex of the parabola occurs at (1/4, 0) or (0.25, 0). Since the coefficient of x^2 is a positive number, then it the parabola opens upward. The vertex is the minimum point on the graph, which happens to occur along the x-axis at (1/4, 0) as the only x-intercept.

Therefore, the graph intersects the x-axis only once, at the vertex.

Please mark my answers as the Brainliest if you find this helpful :)
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Step-by-step explanation:

This is a right triangle:

Hypotenuse: c=3959 mi + 5.9 mi → c=3964.9 mi

Leg 1: a=x=?

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Using the Pytagorean theorem:

a^2+b^2=c^2

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x^2+15,673,681 mi^2=15,720,432.01 mi^2

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