Part A - Construct a circle of any radius, and draw a chord on it. The construct the radius of the circle that bisects the chord
1 answer:
Answer:
It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.
Step-by-step explanation:
i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.
ii. Construct the radius to bisect the chord, dividing it into two equal parts.
Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.
The construction to the question is herewith attached to this answer for more clarifications.
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Using the asymptote concept, the function with a vertical asymptote at x = 3 and an horizontal asymptote at is given by:
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
The vertical asymptote at x = 3 means that x = 3 is a root of the denominator, hence:
The horizontal asymptote at y = -1/2 means that:
Which happens if , hence the function is:
More can be learned about asymptotes at brainly.com/question/16948935
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