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3 years ago

Solve each system of equations algebraically y=x+2y=-3x

Mathematics

1 answer:

elena55 [62]3 years ago

4 0

Answer:

Your answer is: (-1/2, 3/2)

Step-by-step explanation:

y = x + 2

y = -3x

Use substitution by plugging the second equation into the first.

-3x = x +2

Subtract x from both sides to combine the variables.

-4x = 2

Divide both sides by -4 to isolate the variable x.

x = 2/-4

Simplify.

x = -1/2

Plug x into one of the equations to find y.

y = (-1/2) + 2

y = 3/2

Plug x into the other equation to confirm your answer.

y = -3(-1/2)

y = 3/2

Your answer is: (-1/2, 3/2)

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To solve this system by substitution, first isolate x in the second equation.

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Now, plug this expression ( $8-7y$ ) for x in the top equation to solve for y.

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Now that you have y, plug it into the second equation and solve for x.

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Last step is to plug your x- and y-values in to both equations to check your work.

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Read 2 more answers

Solve each system of equations algebraically y=x+2y=-3x​

Solve each system of equations algebraically y=x+2y=-3x