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3 years ago

I need help with this please

Mathematics

2 answers:

bixtya [17]3 years ago

7 0

Answer:

i think it's c but I'm not 100% sure

Alex_Xolod [135]3 years ago

3 0

Answer:

Step-by-step explanation:

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4x-2=3x+4 solve this

Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

x=6

8 0

3 years ago

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Please I really need help with 4 and 5 and attach eligible work

Rudiy27

Answer:

#4= 1

#5= A=9,216

B=360

Step-by-step explanation:

number five x equals 9 and y = 1,024 so it's asking us that if x = 81 what would y = and to get 81 you need to multiply 9 by 9 so all you have to do is multiply 1024 by 9 to get 9,216 so y = 9,216 and the same thing goes for B

6 0

2 years ago

For an independent t-test, if the mean of group 1=10, mean of group 2=12, ss1 =5, ss2=8, there are 6 individuals per group. what

eimsori [14]

The value of t obtained is 4.76

Given,

Mean of group 1, $M_{1}$ = 10

Mean of group 2, $M_{2}$ = 12

$SS_{1}$ = 5

$SS_{2}$ = 8

Number of individuals per group, n = 6

The degrees of freedom are calculated as:

$df = (n_{1} -1)+(n_{2} -1)$ = ( 8-1) + (8-1) = 7 + 7 = 14

The difference between sample means $M_{d}$ is:

$M_{d}$ = $M_{1} -M_{2}$ = 10 - 12 = 2

Here n is equal for both groups which is = 8

Now,

The standard deviation of sample 1 :

$s_{1} =\sqrt{\frac{SS_{1} }{n_{1} -1} } = \sqrt{\frac{5}{8-1} } = \sqrt{\frac{5}{7} } = 0.85$

The standard deviation of sample 2 :

$s_{2}= \sqrt{\frac{SS_{2} }{n_{2}-1 } } = \sqrt{\frac{8}{8-1} } = \sqrt{\frac{8}{7} } = 1.07$

Now, we have to calculate the standard error for the difference of the means.

MSE = $\frac{(n_{1}-1)s^{2} _{1}+(n_{2}-1)s^{2} _{2} }{(n_{1}-1)+(n_{2}-1) }$

= $\frac{(8-1)(0.85^{2})+(8-1)(1.07^{2}) }{(8-1)+(8-1)}$

= $\frac{10.1318}{14}$

MSE = 0.7237

Then, the standard error can be calculated as:

$s_{M_{d} } = \sqrt{\frac{2MSE}{n} } = \sqrt{\frac{2 * 0.7237}{8} } = 0.42$

Now we can calculate t :

$t=\frac{M_{d} }{s_{M_{d} } } = \frac{2}{0.42} = 4.76$

Learn more about standard deviation here : brainly.com/question/16403666

#SPJ4

7 0

2 years ago

The regular hexagonal prism tank is completely filled with water. The tank has a height of 5 ft and the area of its base is 22ft

love history [14]

Answer:

110 ft³ of water

Step-by-step explanation:

Use the prism volume formula, V = Bh, where B is the area of the base and h is the height.

Plug in the area of the base and height, and solve for V:

V = Bh

V = (22)(5)

V = 110

So, the volume is 110 ft³

There is 110 ft³ of water in the tank

6 0

3 years ago

What is the LCM of 16 and 40 ? 24 and 40 ?

andre [41]

Answer:

80 & 120

Step-by-step explanation:

16×5 & 40×2=80

24×5 & 40×3=120

5 0

3 years ago

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